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Path: ...!eternal-september.org!feeder3.eternal-september.org!news.eternal-september.org!.POSTED!not-for-mail From: "Paul.B.Andersen" <relativity@paulba.no> Newsgroups: sci.physics.relativity Subject: Re: Incorrect mathematical integration Date: Wed, 24 Jul 2024 22:45:42 +0200 Organization: A noiseless patient Spider Lines: 64 Message-ID: <v7rp5h$1t5kp$1@dont-email.me> References: <EKV4LWfwyF4mvRIpW8X1iiirzQk@jntp> <v7jnc7$7jpq$1@dont-email.me> <KRDL-sfeKg0KUbMuUiMzTEhYDwk@jntp> <v7mc8d$pmhs$1@dont-email.me> <9w4qQAYIGHNeJtHg4ZR1m_Ooxo4@jntp> <v7p7bu$1cd5m$1@dont-email.me> <oEpFQDJJhcpYoGFheTTVIKntZUE@jntp> <v7qt4k$1obhi$1@dont-email.me> <2DB5P6IpybAncHUWmFdX55lJN7A@jntp> <v7ri3a$1rs1b$1@dont-email.me> <ftN6UmDr7W62aPoOQpYysEUFAh8@jntp> MIME-Version: 1.0 Content-Type: text/plain; charset=UTF-8; format=flowed Content-Transfer-Encoding: 8bit Injection-Date: Wed, 24 Jul 2024 22:45:38 +0200 (CEST) Injection-Info: dont-email.me; posting-host="0c8f57f31bc205e361b3ecf55228bd8d"; logging-data="2004633"; mail-complaints-to="abuse@eternal-september.org"; posting-account="U2FsdGVkX19ZoNLV2l8gI6wo8UmUqJBD" User-Agent: Mozilla Thunderbird Cancel-Lock: sha1:a4aWF/qZANIEP86acvypyqNKlsw= Content-Language: en-GB In-Reply-To: <ftN6UmDr7W62aPoOQpYysEUFAh8@jntp> Bytes: 3350 Den 24.07.2024 20:55, skrev Richard Hachel: > Le 24/07/2024 à 20:44, "Paul.B.Andersen" a écrit : >> Den 24.07.2024 15:08, skrev Richard Hachel >>> >>> Now what does the global ring look like in the proton frame of reference, and above all what is the trajectory of point A during one revolution? >> >> Irrelevant. >> >> The point A is at any instant adjacent to the proton. >> We consider an arbitrary instant I. >> >> Let K(x,t) be an inertial frame of reference which at the instant I >> is momentarily comoving with the point A. >> >> The speed of the proton in K is v = dx/dt = L/T = 0.999999991·c >> >> Do you know another definition of the speed of the proton in K >> than dx/dt ? >> >> Let K'(x',τ) be an inertial frame of reference which at the instant I >> is momentarily comoving with the proton. >> >> The speed of the point A in K' is v' = dx'/dτ = (L/γ)/τ = 0.999999991·c >> >> Do you know another definition of the speed of the point A in K' >> than dx'/dτ ? To the very slow reader R.H: At the instant in question the point A and the momentarily colocated proton can be at any arbitrary point in the circuit, and K and K' are momentarily comoving with the point A and the proton respectively. This means that K and K' are momentarily colocated, and their relative speed is 0.999999991·c. Even the shape of the accelerator (it's not a circle!) is irrelevant. > > It's not a joke, it's a question. > > We take a very large particle accelerator of several kilometers. > > On this particle accelerator, we fix a point A, coordinates (0,0,0) and > we ask to draw the trajectory of the proton in R. > > We assume z=0. > > We then have a large circle. > > We then request a change of reference frame, and we request the > trajectory of point A in the proton reference frame. > > I wish good luck to whoever answers, it's not high school level. > > R.H. And your point is? -- Paul https://paulba.no/