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From: "Fred. Zwarts" <F.Zwarts@HetNet.nl>
Newsgroups: comp.theory
Subject: Re: HHH(DDD) sees the exact same behavior pattern as
 HHH(Infinite_Recursion)
Date: Mon, 29 Jul 2024 09:29:24 +0200
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Op 28.jul.2024 om 22:10 schreef olcott:
> On 7/28/2024 2:14 PM, Fred. Zwarts wrote:
>> Op 28.jul.2024 om 16:25 schreef olcott:
>>> On 7/28/2024 2:59 AM, Fred. Zwarts wrote:
>>>> Op 28.jul.2024 om 05:15 schreef olcott:
>>>>> On 7/27/2024 7:40 PM, Mike Terry wrote:
>>>>>> On 27/07/2024 19:14, Alan Mackenzie wrote:
>>>>>>> olcott <polcott333@gmail.com> wrote:
>>>>>>>
>>>>>>>> Stopping running is not the same as halting.
>>>>>>>> DDD emulated by HHH stops running when its emulation has been 
>>>>>>>> aborted.
>>>>>>>> This is not the same as reaching its ret instruction and 
>>>>>>>> terminating
>>>>>>>> normally (AKA halting).
>>>>>>>
>>>>>>> I think you're wrong, here.  All your C programs are a stand in for
>>>>>>> turing machines.  A turing machine is either running or halted. 
>>>>>>> There is
>>>>>>> no third state "aborted".  An aborted C program certainly doesn't
>>>>>>> correspond with a running turing machine - so it must be a halted 
>>>>>>> turing
>>>>>>> machine.
>>>>>>>
>>>>>>> So aborted programs are halted programs.  If you disagree, 
>>>>>>> perhaps you
>>>>>>> could point out where in my arguments above I'm wrong.
>>>>>>>
>>>>>>
>>>>>> Aborting is an action performed by a simulator, not the TM being 
>>>>>> simulated.
>>>>>>
>>>>>> If we want to count "aborted" as some kind of final status, it 
>>>>>> will have to be the status of a specific /PARTIAL SIMULATOR's/ 
>>>>>> simulation of a given computation.  That's not a property of the 
>>>>>> computation itself, as different partial simulators can simulate 
>>>>>> the same computation and terminate for different reasons.  Like 
>>>>>> HHH(DDD) aborts, while UTM(DDD) simulates to completion and so the 
>>>>>> final simulation status is halts. [Neither of those outcomes 
>>>>>> contradict the fact that the computation DDD() halts.]
>>>>>>
>>>>>> If some partial simulator halts when simulating a computation [as 
>>>>>> with UTM(DDD)] that implies the computation DDD() halts.  But if 
>>>>>> the simulator aborts, it doesn't say that much (in and of itself) 
>>>>>> about whether the /computation/ halts.  The halting problem 
>>>>>> statement is not concerned with simulations or how the simulations 
>>>>>> end.
>>>>>>
>>>>>> Every time anyone in these PO threads says "halts" it ought to be 
>>>>>> 100% clear to everyone whether the computation itself is being 
>>>>>> discussed, or whether some simulation final status is intended. 
>>>>>> (But that's far from being the case!)  Since the halting problem 
>>>>>> is concerned with computations halting and not how partial 
>>>>>> simulations are ended, I suggest that PO explicitly make clear 
>>>>>> that he is referring to simulations, whenever that is the case.  
>>>>>> It seems reasonable that readers seeing "halts" with no further 
>>>>>> clarification can interpret that as actual computation behaviour, 
>>>>>> as that is how the term is always used in the literature.  Same 
>>>>>> with other terms like "reach"...
>>>>>>
>>>>>> So when PO says "DDD simulated by HHH cannot reach its final ret 
>>>>>> instruction" is he talking about the computation DDD() [as defined 
>>>>>> mathematically], or its simulation by HHH?  He means the latter, 
>>>>>> but its far from clear, I'd say!  [I think most readers now have 
>>>>>> come around to reading it as a statement about simulations rather 
>>>>>> than the actual computation, which totally changes things...]
>>>>>>
>>>>>>
>>>>>> Mike.
>>>>>>
>>>>>
>>>>> _DDD()
>>>>> [00002163] 55         push ebp      ; housekeeping
>>>>> [00002164] 8bec       mov ebp,esp   ; housekeeping
>>>>> [00002166] 6863210000 push 00002163 ; push DDD
>>>>> [0000216b] e853f4ffff call 000015c3 ; call HHH(DDD)
>>>>> [00002170] 83c404     add esp,+04
>>>>> [00002173] 5d         pop ebp
>>>>> [00002174] c3         ret
>>>>> Size in bytes:(0018) [00002174]
>>>>>
>>>>> It is a verified fact that DDD emulated by HHH 100% exactly
>>>>> and precisely according to the actual x86 semantics of
>>>>> the emulated code including the recursive call that causes
>>>>> HHH to emulate itself emulating DDD cannot possibly get
>>>>> past it own 0000216b machine address.
>>>>>
>>>>> *Anyone as much as hinting otherwise is not being truthful*
>>>>> If we remove all of the problematic code then this same
>>>>> trace still occurs until it crashes from OOM error.
>>>>>
>>>>
>>>> No matter how much olcott wants it to be correct, or how many times 
>>>> olcott repeats that it is correct, it does not change the fact that 
>>>> such a simulation is incorrect, because it is unable to reach the end.
>>>
>>> It is ridiculously stupid to expect the correct emulation
>>> of a non-halting input to end.
>>
>> Irrelevant nonsense ignored.
>> We are not discussing a non-halting HHH, 
> 
> No we are not. Please don't act so stupidly.

Why are you contradicting yourself so often? It does not look very clever.
You were talking about an infinite set of HHH, some of which abort, some 
of which do not abort.
We all agree that the HHH that do not abort are incorrect, even Olcott 
agrees with it. Therefore, no further discussion is needed about the HHH 
that do not abort. Starting to mention it again is distracting from the 
points of disagreement.

The disagreement that is left is about the HHH that do abort.
Olcott has shown 'traces' of such an HHH when simulating itself.
This proves that after two recursive simulations, HHH aborts its 
simulation and halts.
It is comparible with:

void Finite_Recursion (int N) {
   if (N > 0) Finite_Recursion (N - 1);
}

which also halts after a few recursions.

For some unclear reason, olcott keeps dreaming of the HHH that does not 
abort and he thinks that such dreams should play a role in the logic to 
determine whether the simulation of a halting program is correct.

Olcott's aborting HHH is programmed to abort the simulation after N 
cycles of recursive simulations. Therefore, it is incorrect to abort the 
simulation of HHH when the simulated HHH has performed only N-1 cycles, 
because that changes the behaviour of the simulated HHH.
Since the simulated HHH always runs one cycle behind the simulating HHH, 
it is clear that HHH can never simulate enough cycles for a correct 
simulation, as is required by the x86 language.
Therefore, the simulation is incomplete and therefore incorrect 
according to the criteria olcott stipulated.
The conclusion is simple:
HHH cannot possibly simulate itself correctly.

No matter how much olcott wants it to be correct, or how many times 
olcott repeats that it is correct, it does not change the fact that such 
a simulation is incorrect, because it is unable to reach the end.
Olcott's own claim that the simulated HHH does not reach its end 
confirms it. The trace he has shown also proves that HHH cannot reach 
the end of its own simulation. So, his own claims prove that it is true 
that HHH cannot possibly simulate itself up to the end, which makes the 
simulation incomplete and, therefore, incorrect.

Sipser would agree that this incorrect simulation cannot be used to 
detect a non-halting behaviour.