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Path: ...!eternal-september.org!feeder3.eternal-september.org!news.eternal-september.org!.POSTED!not-for-mail
From: olcott <polcott333@gmail.com>
Newsgroups: comp.theory
Subject: Re: Hypothetical possibilities --- Sipser approved criteria
Date: Mon, 29 Jul 2024 11:25:27 -0500
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On 7/28/2024 3:21 AM, Mikko wrote:
> On 2024-07-27 14:59:34 +0000, olcott said:
> 
>> On 7/27/2024 9:50 AM, Alan Mackenzie wrote:
>>> olcott <polcott333@gmail.com> wrote:
>>>> On 7/27/2024 1:54 AM, Mikko wrote:
>>>
>>>>> If a simulator correctly simulates a finite number of instructions
>>>>> where x86 program specifies an execution of an infinite number of
>>>>> instructions then the simulation deviates from x86 semantics at the
>>>>> point where the simulation stops but the x86 semantics specify
>>>>> countinuation.
>>>
>>>> I paraphrase this as the requirement for a termination analyzer
>>>> to never terminate. That *is* a ridiculously stupid requirement.
>>>
>>> I think you would do better to "paraphrase" it that a correct simulator
>>> cannot always be a termination analyser.  The two are different things.
>>>
>>
>> *When you say if backwards (like that) it makes less sense*
>> A correct termination analyzer can always be based on a correct 
>> simulator using this criteria:
>>
>> <MIT Professor Sipser agreed to ONLY these verbatim words 10/13/2022>
>>      If simulating halt decider H correctly simulates its input D
>>      until H correctly determines that its simulated D would never
>>      stop running unless aborted then
>>
>>      H can abort its simulation of D and correctly report that D
>>      specifies a non-halting sequence of configurations.
>> </MIT Professor Sipser agreed to ONLY these verbatim words 10/13/2022>
> 
> The quoted criterion requires a partial simulation that discontinues the
> simulation in a situation where the input specifies that the execution
> must be continued.
> 
> It also requires that the analyzer must be able to determine whithout
> simulation whether the unsimulated behaviour ever terminates.

void Infinite_Recursion()
{
   Infinite_Recursion();
}

_Infinite_Recursion()
[0000215a] 55         push ebp      ; 1st line
[0000215b] 8bec       mov ebp,esp   ; 2nd line
[0000215d] e8f8ffffff call 0000215a ; 3rd line
[00002162] 5d         pop ebp
[00002163] c3         ret
Size in bytes:(0010) [00002163]

Begin Local Halt Decider Simulation   Execution Trace Stored at:113934
[0000215a][00113924][00113928] 55         push ebp      ; 1st line
[0000215b][00113924][00113928] 8bec       mov ebp,esp   ; 2nd line
[0000215d][00113920][00002162] e8f8ffffff call 0000215a ; 3rd line
[0000215a][0011391c][00113924] 55         push ebp      ; 1st line
[0000215b][0011391c][00113924] 8bec       mov ebp,esp   ; 2nd line
[0000215d][00113918][00002162] e8f8ffffff call 0000215a ; 3rd line
Local Halt Decider: Infinite Recursion Detected Simulation Stopped

If you cannot see that the above x86 machine code proves that
it will never halt then you can't possibly understand what I
have been saying.

It is like you reject mathematical induction as a wild guess.

>  In some
> cases this is determinable but no analyzer can determine it in all
> cases. Your attempt does it right in some cases but gets wrong the
> case that many consider the most interesting.
> 

-- 
Copyright 2024 Olcott "Talent hits a target no one else can hit; Genius
hits a target no one else can see." Arthur Schopenhauer