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Path: ...!eternal-september.org!feeder3.eternal-september.org!news.eternal-september.org!.POSTED!not-for-mail
From: Mikko <mikko.levanto@iki.fi>
Newsgroups: comp.theory
Subject: Re: No decider is ever accountable for the behavior of the computation that itself is contained within
Date: Thu, 1 Aug 2024 10:40:54 +0300
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On 2024-07-30 23:20:43 +0000, olcott said:

> On 7/30/2024 1:56 AM, Mikko wrote:
>> On 2024-07-29 16:32:00 +0000, olcott said:
>> 
>>> On 7/28/2024 3:40 AM, Mikko wrote:
>>>> On 2024-07-27 14:21:50 +0000, olcott said:
>>>> 
>>>>> On 7/27/2024 2:46 AM, Mikko wrote:
>>>>>> On 2024-07-26 16:28:43 +0000, olcott said:
>>>>>> 
>>>>>>> No decider is ever accountable for the behavior of the
>>>>>>> computation that itself is contained within.
>>>>>> 
>>>>>> That claim is fully unjustified. How do you even define "accountable"
>>>>>> in the context of computations, automata, and deciders?
>>>>> 
>>>>> int sum(int x, int y){ return x + y; }
>>>>> sum(5,6) is not accountable for reporting sum(3,2).
>>>> 
>>>> That claim is fully unjustified. How do you even define "accountable"
>>>> in the context of computations, automata, and deciders?
>>>> 
>>>>> It computes the mapping from its input to the value of their sum.
>>>> 
>>>> That's obvious but is it relevant?
>>>> 
>>>>> HHH must compute the mapping from its input finite string
>>>>> of the x86 machine code of DDD to the behavior that this
>>>>> finite string specifies and then report on the halt status
>>>>> of this behavior.
>>>> 
>>>> Now is that relevant?
>>> 
>>> Halt deciders report the halt status on the basis
>>> of the behavior that a finite string input specifies.
>> 
>> How is that relevant?
> 
> Computable functions are the formalized analogue of the intuitive 
> notion of algorithms, in the sense that a function is computable if 
> there exists an algorithm that can do the job of the function, i.e. 
> *given an* *input of the function domain it can return the 
> corresponding output* https://en.wikipedia.org/wiki/Computable_function

How is that relevant?

The question is still unanswered. Apparently the answer is "no way" or
an answer would already be given.

-- 
Mikko