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Path: ...!weretis.net!feeder8.news.weretis.net!eternal-september.org!feeder3.eternal-september.org!news.eternal-september.org!.POSTED!not-for-mail From: "Fred. Zwarts" <F.Zwarts@HetNet.nl> Newsgroups: comp.theory Subject: Re: Any honest person that knows the x86 language can see... predict correctly Date: Thu, 1 Aug 2024 16:10:42 +0200 Organization: A noiseless patient Spider Lines: 59 Message-ID: <v8g513$26s53$2@dont-email.me> References: <v887np$gl15$1@dont-email.me> <v8a2j5$u4t6$1@dont-email.me> <v8asse$12hr3$2@dont-email.me> <v8aukp$12grj$1@dont-email.me> <v8b00m$12ojm$1@dont-email.me> <v8bchs$15ai5$1@dont-email.me> <v8bh32$15une$1@dont-email.me> <d89f03c5a605f010ec3c83c50137b983dc85848e@i2pn2.org> <v8bl2j$16ibk$2@dont-email.me> <tiuiaj5jf0jqcfcfntko5hufisp8mb93bm@4ax.com> <v8bu91$18b7k$2@dont-email.me> <ddb7a467da20b6a6bd90aee9735a62ae68cac50e.camel@gmail.com> <v8f0ni$204k7$1@dont-email.me> <v8fehe$22ege$1@dont-email.me> <v8fssh$24rl1$5@dont-email.me> <v8g0l3$24u77$2@dont-email.me> <v8g14o$25l0a$9@dont-email.me> MIME-Version: 1.0 Content-Type: text/plain; charset=UTF-8; format=flowed Content-Transfer-Encoding: 8bit Injection-Date: Thu, 01 Aug 2024 16:10:44 +0200 (CEST) Injection-Info: dont-email.me; posting-host="8c0ac17c3f9e00decd2248743b2f1a16"; logging-data="2322595"; mail-complaints-to="abuse@eternal-september.org"; posting-account="U2FsdGVkX181vBj3HwGDPRLJLhuuIH3w" User-Agent: Mozilla Thunderbird Cancel-Lock: sha1:HqMC3TGJbQFDK0yXc0NBF6i+umw= Content-Language: en-GB In-Reply-To: <v8g14o$25l0a$9@dont-email.me> Bytes: 3602 Op 01.aug.2024 om 15:04 schreef olcott: > On 8/1/2024 7:56 AM, Fred. Zwarts wrote: >> Op 01.aug.2024 om 13:51 schreef olcott: >>> On 8/1/2024 2:46 AM, Fred. Zwarts wrote: >>>> Op 01.aug.2024 om 05:51 schreef olcott: >>>>> On 7/31/2024 10:08 PM, wij wrote: >>>>>> On Tue, 2024-07-30 at 18:50 -0500, olcott wrote: >>>>>>> >>>>>>> It is not supposed to be a general solution to the halting problem. >>>>>>> it only shows how the "impossible" input is correctly determined >>>>>>> to be non halting. >>>>>>> >>>>>> >>>>>> But how do you determine it is non-halting? >>>>>> >>>>>> As I know you are even unable to define what 'halt' mean !!! >>>>>> >>>>> I have done this thousands of times and after someone >>>>> has read these thousands of times they say that I never >>>>> said it once. >>>>> >>>>> void DDD() >>>>> { >>>>> HHH(DDD); >>>>> return; >>>>> } >>>>> >>>>> int main() >>>>> { >>>>> HHH(DDD); >>>>> } >>>>> >>>>> If DDD correctly emulated by HHH cannot possibly >>>>> reach its return instruction then it never halts. >>>>> >>>>> >>>> >>>> But a correct simulation is impossible. >>> >>> When HHH does what-ever-the-hell the x86 semantics specifies >>> then HHH is correct. >>> >> >> But since HHH deviates from the semantics of the x86 language (by >> skipping instructions of a halting program) it is incorrect. >> > > Only a freaking moron would believe that a non > terminating input should be simulated forever. > We are not talking about your dreams of a non aborting HHH. We are talking about an aborting HHH which terminates. So, who is the freaking moron talking about non-terminating input? Dreams are no substitute for fact or for logic. Skipping the last cycle of the simulation of HHH, which aborts after two cycles, is a deviation from the semantics of the x86 language. But, you are a slow learner. Probably you will repeat the same error another thousand times.