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From: Mikko <mikko.levanto@iki.fi>
Newsgroups: comp.theory
Subject: Re: Any honest person that knows the x86 language can see... predict correctly
Date: Fri, 2 Aug 2024 12:28:39 +0300
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On 2024-08-01 11:51:45 +0000, olcott said:

> On 8/1/2024 2:46 AM, Fred. Zwarts wrote:
>> Op 01.aug.2024 om 05:51 schreef olcott:
>>> On 7/31/2024 10:08 PM, wij wrote:
>>>> On Tue, 2024-07-30 at 18:50 -0500, olcott wrote:
>>>>> 
>>>>> It is not supposed to be a general solution to the halting problem.
>>>>> it only shows how the "impossible" input is correctly determined
>>>>> to be non halting.
>>>>> 
>>>> 
>>>> But how do you determine it is non-halting?
>>>> 
>>>> As I know you are even unable to define what 'halt' mean !!!
>>>> 
>>> I have done this thousands of times and after someone
>>> has read these thousands of times they say that I never
>>> said it once.
>>> 
>>> void DDD()
>>> {
>>>    HHH(DDD);
>>>    return;
>>> }
>>> 
>>> int main()
>>> {
>>>    HHH(DDD);
>>> }
>>> 
>>> If DDD correctly emulated by HHH cannot possibly
>>> reach its return instruction then it never halts.
>>> 
>>> 
>> 
>> But a correct simulation is impossible.
> 
> When HHH does what-ever-the-hell the x86 semantics specifies
> then HHH is correct.

When HHH does not do what-ever-the-hell the x86 semantics specifies
the HHH is incorrect.

-- 
Mikko