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From: olcott <polcott333@gmail.com>
Newsgroups: comp.theory
Subject: Re: Who knows that DDD correctly simulated by HHH cannot possibly
 reach its own return instruction final state?
Date: Sun, 4 Aug 2024 08:53:34 -0500
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On 8/4/2024 1:22 AM, Fred. Zwarts wrote:
> Op 03.aug.2024 om 18:35 schreef olcott:
 >>>> ∞ instructions of DDD correctly emulated by HHH[∞] never
>> reach their own "return" instruction final state.
>>
>> So you are saying that the infinite one does?
>>
> 
> Dreaming again of HHH that does not abort? Dreams are no substitute for 
> facts.
> The HHH that aborts and halts, halts. A tautology.

void DDD()
{
   HHH(DDD);
   return;
}

That is the right answer to the wrong question.
I am asking whether or not DDD emulated by HHH
reaches its "return" instruction.

> The correct simulation of a halting program halts. A truism.
> HHH cannot possibly simulate itself correctly.
> 

So by correctly you must mean that HHH incorrectly
skips the call from DDD to HHH(DDD).

> I am happy that you were not a member of our team when we developed 
> simulators to check the design of big detector systems.

Crash dummy simulators?
Not x86 emulators.

> We knew that a simulation is only correct if it matches the reality. But 
> you seem to think that it is correct that a simulator does not match the 
> reality.

The reality is that DDD does call HHH(DDD) in recursive
simulation. When you ignore this then you are out-of-touch
with reality.

-- 
Copyright 2024 Olcott "Talent hits a target no one else can hit; Genius
hits a target no one else can see." Arthur Schopenhauer