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Path: ...!eternal-september.org!feeder3.eternal-september.org!news.eternal-september.org!.POSTED!not-for-mail
From: olcott <abc@def.com>
Newsgroups: comp.theory
Subject: Re: Who knows that DDD correctly simulated by HHH cannot possibly
 reach its own return instruction final state?
Date: Mon, 5 Aug 2024 19:07:41 -0500
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On 8/5/2024 5:59 PM, Richard Damon wrote:
> On 8/5/24 9:49 AM, olcott wrote:
>> On 8/5/2024 2:39 AM, Mikko wrote:
>>> On 2024-08-04 18:59:03 +0000, olcott said:
>>>
>>>> On 8/4/2024 1:51 PM, Richard Damon wrote:
>>>>> On 8/4/24 9:53 AM, olcott wrote:
>>>>>> On 8/4/2024 1:22 AM, Fred. Zwarts wrote:
>>>>>>> Op 03.aug.2024 om 18:35 schreef olcott:
>>>>>>  >>>> ∞ instructions of DDD correctly emulated by HHH[∞] never
>>>>>>>> reach their own "return" instruction final state.
>>>>>>>>
>>>>>>>> So you are saying that the infinite one does?
>>>>>>>>
>>>>>>>
>>>>>>> Dreaming again of HHH that does not abort? Dreams are no 
>>>>>>> substitute for facts.
>>>>>>> The HHH that aborts and halts, halts. A tautology.
>>>>>>
>>>>>> void DDD()
>>>>>> {
>>>>>>    HHH(DDD);
>>>>>>    return;
>>>>>> }
>>>>>>
>>>>>> That is the right answer to the wrong question.
>>>>>> I am asking whether or not DDD emulated by HHH
>>>>>> reaches its "return" instruction.
>>>>>
>>>>> But the "DDD emulated by HHH" is the program DDD above,
>>>>
>>>> When I say DDD emulated by HHH I mean at any level of
>>>> emulation and not and direct execution.
>>>
>>> If you mean anything other than what the words mean you wihout
>>> a definition in the beginning of the same message then it is
>>> not reasonable to expect anyone to understand what you mean.
>>> Instead people may think that you mean what you say or that
>>> you don't know what you are saying.
>>>
>>
>> If you don't understand what the word "emulate" means look it up.
>>
>> DDD (above) cannot possibly reach its own "return" instruction halt
>> state when its machine code is correctly emulated by HHH.
>>
> 
> Only because an HHH that does so never returns to anybody.
> 

Do you really not understand that recursive emulation <is>
isomorphic to infinite recursion?

void Infinite_Recursion()
{
   Infinite_Recursion();
   return;
}

Does infinite recursion ever reach its own "return"
instruction halt state?



-- 
Copyright 2024 Olcott "Talent hits a target no one else can hit; Genius
hits a target no one else can see." Arthur Schopenhauer