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From: "Chris M. Thomasson" <chris.m.thomasson.1@gmail.com>
Newsgroups: sci.logic,sci.math
Subject: Re: Replacement of Cardinality
Date: Tue, 6 Aug 2024 16:46:33 -0700
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On 8/6/2024 2:02 PM, Moebius wrote:
> Am 06.08.2024 um 22:21 schrieb Chris M. Thomasson:
>> On 8/6/2024 6:33 AM, Moebius wrote:
>>> Am 06.08.2024 um 04:24 schrieb Chris M. Thomasson:
>>>
>>>> There are infinite[ly many] even[ numbers] and
>>>> there are infinite[ly many] odd[ numbers].
>>>
>>> On the other hand, some even numbers are odd. :-)
>>
>> ;^D 666?
>>
>> Ahh zero. I think its even... ;^)
>>
>> 1, 2, 3, 4, ...
>>
>> odd, even, odd, even, ...
>>
>> So, the pattern:
>>
>> -2, -1, 0, 1, 2
>>
>> even, odd, (even), odd, even
> 
> Yes. An integer z is even, iff there is am integer k such that z = 2k.
> 
> Clearly for z = 0 there is an integer k (namely 0) such that z = 2k.
> 
> In other words, an integer z is even if it can be deviede by 2 "without 
> a remainder =/= 0".
> 
> Clearly 0 can be devided by 2 "without a remainder =/= 0": 0 / 2 = 0.
> 
> So 0 is an odd even number? :-)

I say even? Well, both (odd and even) at the same time? This makes me 
think of signed zero...

+0
-0

and just, 0?

(-2)->(-1)->(-0+)->(+1)->(+2)

? ;^)

so going from -2, -1, -0 means we got to zero from the negative side.

+2, +1, +0 means we got to zero from the positive side.

0 is just zero?

-0+ ? wtf! ;^)