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From: olcott <abc@def.com>
Newsgroups: comp.theory
Subject: Re: Who here is too stupid to know that DDD correctly simulated by
 HHH cannot possibly reach its own return instruction?
Date: Wed, 7 Aug 2024 08:01:33 -0500
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On 8/7/2024 3:16 AM, Fred. Zwarts wrote:
> Op 04.aug.2024 om 15:11 schreef olcott:
>> On 8/4/2024 1:26 AM, Fred. Zwarts wrote:
>>> Op 03.aug.2024 om 17:20 schreef olcott:>>
>>>> When you try to show how DDD simulated by HHH does
>>>> reach its "return" instruction you must necessarily
>>>> must fail unless you cheat by disagreeing with the
>>>> semantics of C. That you fail to have a sufficient
>>>> understanding of the semantics of C is less than no
>>>> rebuttal what-so-ever.
>>>
>>> Fortunately that is not what I try, because I understand that HHH 
>>> cannot possibly simulate itself correctly.
>>>
>>
>> void DDD()
>> {
>>    HHH(DDD);
>>    return;
>> }
>>
>> In other words when HHH simulates itself simulating DDD it
>> is supposed to do something other than simulating itself
>> simulating DDD ???  Do you expect it to make a cup of coffee?
>>
> 
> Is English too difficult for you. I said HHH cannot do it correctly.

*According to an incorrect criteria of correct*
You keep trying to get away with disagreeing with
the semantics of the x86 language. *That is not allowed*

-- 
Copyright 2024 Olcott "Talent hits a target no one else can hit; Genius
hits a target no one else can see." Arthur Schopenhauer