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Path: ...!weretis.net!feeder8.news.weretis.net!eternal-september.org!feeder3.eternal-september.org!news.eternal-september.org!.POSTED!not-for-mail From: "B. Pym" <Nobody447095@here-nor-there.org> Newsgroups: comp.lang.lisp Subject: Re: SBCL complains where Lispwork does not: loop for i for j Date: Wed, 7 Aug 2024 18:40:53 -0000 (UTC) Organization: A noiseless patient Spider Lines: 25 Message-ID: <v90f3h$39c5h$1@dont-email.me> MIME-Version: 1.0 Content-Type: text/plain; charset=iso-8859-1 Injection-Date: Wed, 07 Aug 2024 20:40:54 +0200 (CEST) Injection-Info: dont-email.me; posting-host="7094501a9f209988b45d39573ac7d250"; logging-data="3453105"; mail-complaints-to="abuse@eternal-september.org"; posting-account="U2FsdGVkX18F9bLjCRU3vnfDCBPtsDXi" User-Agent: XanaNews/1.18.1.6 Cancel-Lock: sha1:gvzo2yut/4SdPxkP2vo0WYLXlzM= Bytes: 1469 Jochen wrote: > > This ... > > > > CL-USER 1 > (loop for i for j in '(a b c) collect (cons i j)) > > => ((0 . A) (1 . B) (2 . C)) > > > > works perfectly on LispWorks, but not with SBCL > > > > => FOR is an unknown keyword in FOR or AS clause in LOOP. > > > > I found a way around it 'for i from 0' but am not sure if there is > > another smarter way to achieve this. > > I think the canonical way would be > > (loop for i upfrom 0 > for j in '(a b c) > collect (cons i j)) newLISP (map (curry list $idx) '(a b c)) ((0 a) (1 b) (2 c))