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Path: ...!news.mixmin.net!eternal-september.org!feeder3.eternal-september.org!news.eternal-september.org!.POSTED!not-for-mail From: Python <python@invalid.org> Newsgroups: sci.logic,sci.math Subject: Re: Replacement of Cardinality Date: Thu, 15 Aug 2024 19:06:15 +0200 Organization: CCCP Lines: 39 Message-ID: <v9lci7$trev$22@dont-email.me> References: <hsRF8g6ZiIZRPFaWbZaL2jR1IiU@jntp> <6c471296-90b8-4cf7-bc9b-480bd34ef190@att.net> <v93n0s$b7a2$4@dont-email.me> <1f25a3d6-7b0e-476d-aa99-ecb003cf763f@att.net> <b0XFTJvTommasLo9Ns10OeW0TN0@jntp> <75e2ce0e-7df8-4266-968b-9c58e4140b03@att.net> <RCAlRuRy_RKB_tYItKJs7fNcIs0@jntp> <35d8c0a1-dab3-4c15-8f24-068e8200cb07@att.net> <sglIw8p3PCeHivaAhg-7IVZCN4A@jntp> <fcd3f5f1-fd6e-44ac-823d-fa567d5fb9ba@att.net> <t_rVz7RU7M3aHZTB1TQJS59Ez0I@jntp> <45ad1007-b1a7-49d0-a650-048f02738226@att.net> <v9lc9n$10teg$3@dont-email.me> MIME-Version: 1.0 Content-Type: text/plain; charset=UTF-8; format=flowed Content-Transfer-Encoding: 8bit Injection-Date: Thu, 15 Aug 2024 19:06:15 +0200 (CEST) Injection-Info: dont-email.me; posting-host="bb99e0d8757e7fde2ac17fffb9b51d81"; logging-data="978399"; mail-complaints-to="abuse@eternal-september.org"; posting-account="U2FsdGVkX19LnYkVaV54V/Puq5XFlyaC" User-Agent: Mozilla Thunderbird Cancel-Lock: sha1:O7s0N0az65M9jnXgU9MXcjUBTtQ= Content-Language: en-US In-Reply-To: <v9lc9n$10teg$3@dont-email.me> Bytes: 2965 Le 15/08/2024 à 19:01, Moebius a écrit : > Am 13.08.2024 um 19:02 schrieb Jim Burns: >> On 8/13/2024 10:21 AM, WM wrote: > >>> [There is] a real [number] x with NUF(x) = 1. >> >> INVNUF(1) > ⅟ ⌊⅟INVNUF(1) +1⌋ > ⅟ ⌊⅟INVNUF(1) +2⌋ >> >> NUF(INVNUF(1)) > 1 >> Contradiction. > > Well, no, this just isn't a proof, sorry about that, Jim. > > (Hint: The term "INVNUF(1)" is not defined. Hence you may not even use > it in a proof by contradiction. Actually, you didn't state an assumption > in your "proof".) > > Proof by contradiction: > > Assume that there is an x e IR such that NUF(x) = 1. Let x0 e IR such > that NUF(x0) = 1. This means that there is exactly one unit fraction u > such that u < x0. Let's call this unit fraction u0. Then (by definition) > there is a (actually exactly one) natural number n such that u0 = 1/n. > Let n0 e IN such that u0 = 1/n0. But then (again by definition) 1/(n0 + > 1) is an unit fraction which is smaller than u0 and hence smaller than > x0. Hence NUF(x0) > 1. Contradiction! > > (Of course, it's clear that I'm using the same "proof idea" as you used > in your attempt of a proof.) Of course you are right. 100% right. Any marginally decent high school student could sketch up the very same proof you've posted. Our problem, as a community, is not proving Wolfgang Mückenheim wrong. Our problem, as a community, is that this crook is actually teaching in an academic institution.