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From: David Brown <david.brown@hesbynett.no>
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Date: Fri, 16 Aug 2024 11:42:43 +0200
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On 16/08/2024 02:08, Ben Bacarisse wrote:
> Bart <bc@freeuk.com> writes:
> 

>>
>> In general there is no reason, in a language with true call-by-reference,
>> why any parameter type T (which has the form U*, a pointer to anything),
>> cannot be passed by reference. It doesn't matter whether U is an array type
>> or not.
> 
> I can't unravel this.  Take, as a concrete example, C++.  You can't pass
> a pointer to function that takes an array passed by reference.  You can,
> of course, pass a pointer by reference, but that is neither here nor
> there.
>   

In C++, you can't pass arrays as parameters at all - the language 
inherited C's handling of arrays.  You can, of course, pass objects of 
std::array<> type by value or by reference, just like any other class types.