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From: olcott <polcott333@gmail.com>
Newsgroups: comp.theory
Subject: Re: Anyone that disagrees with this is not telling the truth ---- V4
Date: Mon, 19 Aug 2024 07:14:22 -0500
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On 8/19/2024 5:17 AM, Fred. Zwarts wrote:

*Everything that is not expressly stated below is*
*specified as unspecified*

void DDD()
{
   HHH(DDD);
   return;
}

_DDD()
[00002172] 55         push ebp      ; housekeeping
[00002173] 8bec       mov ebp,esp   ; housekeeping
[00002175] 6872210000 push 00002172 ; push DDD
[0000217a] e853f4ffff call 000015d2 ; call HHH(DDD)
[0000217f] 83c404     add esp,+04
[00002182] 5d         pop ebp
[00002183] c3         ret
Size in bytes:(0018) [00002183]

*It is a basic fact that DDD emulated by HHH according to*
*the semantics of the x86 language cannot possibly stop*
*running unless aborted* (out of memory error excluded)

X = DDD emulated by HHH∞ according to the semantics of the x86 language
Y = HHH∞ never aborts its emulation of DDD
Z = DDD never stops running

My claim boils down to this: (X ∧ Y) ↔ Z

void EEE()
{
   HERE: goto HERE;
}

HHHn correctly predicts the behavior of DDD the same
way that HHHn correctly predicts the behavior of EEE.

>>
> 
> Which proves that the simulation failed to reach the end. This makes the 
> simulation incomplete and therefore incorrect.
> The simulating HHH is programmed to abort and halt. The simulated HHH 
> should behave exactly in the same way, so no cheating with the Root 
> variable is allowed.
> The the simulating HHH aborts when the simulated HHH has only one cycle 
> to go, after which it would also abort and halt, but the simulating HHH 
> failed to reach this end.

I made my claim more precise.

-- 
Copyright 2024 Olcott "Talent hits a target no one else can hit; Genius
hits a target no one else can see." Arthur Schopenhauer