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From: "Paul.B.Andersen" <relativity@paulba.no>
Newsgroups: sci.physics.relativity
Subject: Re: Sync two clocks
Date: Thu, 22 Aug 2024 12:28:28 +0200
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Den 21.08.2024 22:20, skrev Richard Hachel:
> Le 21/08/2024 à 20:41, "Paul.B.Andersen" a écrit :
>> Den 20.08.2024 17:12, skrev Richard Hachel:
>>> Le 20/08/2024 à 15:39, Python a écrit :
>>>
>>>> Hachel now pretends that tB − tA = t'A − tB can be true or false
>>>> depending on the observer.

>>>
>>> This is what I have always said for at least 
>>> 40 years.
>>>

>>
>> Richard, read your watch NOW. Write down the time nn:nn:nn.
>> The time nn:nn:nn is a proper time (read off a clock), it is
>> invariant, not depending on frame of reference.
>>
>> Nobody can have another opinion of what time YOU read off YOUR watch.

Or is your deeper and more intelligent opinion that the time YOU
read off YOUR watch depend on the observer?
Can I have the opinion that you read something else off your watch
than you did?

>>
>> How is it possible to fail to understand this?
>>
>> If we have two stationary clocks in an inertial frame,
>>   and clock A shows tA = t1 when it emits light,
>>   and clock B shows tB = t1 + td when the light hits it,
>>   and clock A shows tA'= t1 + 2⋅td when it is hit by the reflected light,
>>
>> then tA, tB, tA', t1 and td are all proper times which are frame
>> independent (invariants) and "the same for all".
>>
>>   tB − tA = t'A − tB = td
>>
>> The transit time td is a frame independent invariant and
>> the same in both directions, which means that the clocks according
>> to Einstein's _definition_ are synchronous in the inertial frame.
>>
>>
>> Note this:
>> -----------
>> It is an indisputable FACT that according to Einstein's definition
>> the clocks are synchronous in the inertial frame.
>>
>> It is not possible to have different opinions about this.

> 
> Yes, it is possible to have a much deeper and more intelligent opinion 
> on the matter.

Does that mean that your deeper and more intelligent opinion is
that it is NOT a fact that according to Einstein's definition
the clocks are synchronous in the inertial frame?

> 
> I am surprised by the stupidity (I do not say this maliciously but with 
> sadness) of those who read me, and who, surprised, do not understand 
> anything at all of what I explain to them.
> 

See? You don't even try to address what I write, you flee,
whining about why nobody acknowledge your genius.

You never EXPLAIN anything. You only CLAIM a lot of nonsense.

But now you have the opportunity to EXPLAIN why the clocks
according to Einstein's definition are NOT synchronous in
the inertial frame.

Can you do that?

If we have two stationary clocks in an inertial frame,
  and clock A shows tA = t1 when it emits light,
  and clock B shows tB = t1 + td when the light hits it,
  and clock A shows tA'= t1 + 2⋅td when it is hit by the reflected light,

then tA, tB, tA', t1 and td are all proper times which are frame
independent (invariants) and "the same for all".

  tB − tA = t'A − tB = td

The transit time td is a frame independent invariant and
the same in both directions, which means that the clocks according
to Einstein's _definition_ are synchronous in the inertial frame.

--------------

I bet you will flee the challenge yet again. Prove me wrong!

-- 
Paul

https://paulba.no/