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Path: ...!eternal-september.org!feeder3.eternal-september.org!news.eternal-september.org!.POSTED!not-for-mail From: "Paul.B.Andersen" <relativity@paulba.no> Newsgroups: sci.physics.relativity Subject: Re: The problem of relativistic synchronisation Date: Sun, 1 Sep 2024 11:58:17 +0200 Organization: A noiseless patient Spider Lines: 58 Message-ID: <vb1dpe$1evqr$1@dont-email.me> References: <m_uze6jFLkrMPuR4XaNmQntFPLY@jntp> <va9tpv$te1n$1@dont-email.me> <uFAyL-g_jsWF5wwLXINmyrzxquo@jntp> <vaa4om$sicr$16@dont-email.me> <tAXYNx1-wzYUg_H0N6FWnLiQgFs@jntp> <vasgsq$go2j$1@dont-email.me> <TjDY9uUVn5uYrwKeP_H1Mk0G5x8@jntp> <ljfrjfF3hr1U1@mid.individual.net> <IqoVDZIyxVoLReItZ3sD4aYyQ64@jntp> <vavtbs$14qma$1@dont-email.me> <pheofpwVPcOT3RCuNcESEqS47x0@jntp> MIME-Version: 1.0 Content-Type: text/plain; charset=UTF-8; format=flowed Content-Transfer-Encoding: 8bit Injection-Date: Sun, 01 Sep 2024 11:57:03 +0200 (CEST) Injection-Info: dont-email.me; posting-host="2da7522074c47b627b02d4524a400741"; logging-data="1539931"; mail-complaints-to="abuse@eternal-september.org"; posting-account="U2FsdGVkX19MRMjewmryvg1+AiW47cMq" User-Agent: Mozilla Thunderbird Cancel-Lock: sha1:VQUYe5MlonHd04RYRiWXhnLFdsM= Content-Language: en-GB In-Reply-To: <pheofpwVPcOT3RCuNcESEqS47x0@jntp> Bytes: 3050 Den 31.08.2024 23:14, skrev Richard Hachel: > Le 31/08/2024 à 22:10, "Paul.B.Andersen" a écrit : >> Den 31.08.2024 09:05, skrev Richard Hachel: > > >> https://paulba.no/pdf/Mutual_time_dilation.pdf > > ? ? ? Thanks to Python, I see that you fail to understand the very first equation in the paper. https://ibb.co/7C0S4nJ It probably won't help, but I will point out what is clearly defined in the paper. https://paulba.no/pdf/Mutual_time_dilation.pdf Quote: | Event E₂: clock A and clock B' are adjacent | In frame K', A will be at the position -d when B' shows t₂'= d/v I considered this to be obvious for a reasonable knowledgeable reader. Explanation for the less knowledgeable reader: ----------------------------------------------- In frame K' the clock A has moved from the position X' = 0 to the position x' = -d with the speed v. Since t' = 0 when A was at x' = 0, t' = d/v when A is at x' = -d. So the coordinates of event E₂ in K' are x₂'= -d, t₂' = d/v In frame K the temporal coordinate will be: t₂ = γ⋅(t₂' + (v/c²)⋅x₂') = equation (1) in the paper The spatial coordinate was irrelevant, but it would be: x₂ = γ⋅(x₂' + v⋅t₂') = γ⋅(-d + v⋅d/v) = 0 which is a trivial result since clock A is stationary at x = 0. -------------- Your d' is probably the distance between the clocks in K measured in frame K', and vice versa. But this 'contacted' distance is never used, and is irrelevant. In the Lorentz transform you never use contacted distances and dilated times. You _only_ use proper distances and proper times. Didn't you know that? -- Paul https://paulba.no/