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Path: ...!weretis.net!feeder8.news.weretis.net!eternal-september.org!feeder3.eternal-september.org!news.eternal-september.org!.POSTED!not-for-mail From: "Paul.B.Andersen" <relativity@paulba.no> Newsgroups: sci.physics.relativity Subject: Re: The problem of relativistic synchronisation Date: Thu, 5 Sep 2024 22:19:40 +0200 Organization: A noiseless patient Spider Lines: 40 Message-ID: <vbd3m9$famd$1@dont-email.me> References: <m_uze6jFLkrMPuR4XaNmQntFPLY@jntp> <2VJMHmUL3oTjzHTxkbHeeVgwp1A@jntp> <vb2tvf$1ls0b$1@dont-email.me> <vb4sas$2u11j$1@dont-email.me> <FwN11HvPTqkgQgrbwnddFC1OY98@jntp> <vb79g4$3cout$1@dont-email.me> <FUkaOI4ar_TcsN7KN74WFA8f3Yw@jntp> <vbactr$3v15v$1@dont-email.me> <aUNR2GXBkc_bVoYI-Y6TV491wuE@jntp> <vbc7tk$at7q$2@dont-email.me> <cRRzT6nOqvNsNZkRCWbRl5usaUY@jntp> MIME-Version: 1.0 Content-Type: text/plain; charset=UTF-8; format=flowed Content-Transfer-Encoding: 8bit Injection-Date: Thu, 05 Sep 2024 22:18:17 +0200 (CEST) Injection-Info: dont-email.me; posting-host="b4a36dbefc7e4a8f358230e5838ec27f"; logging-data="502477"; mail-complaints-to="abuse@eternal-september.org"; posting-account="U2FsdGVkX19Lxa2KTSv3lrsjrOLUhgg/" User-Agent: Mozilla Thunderbird Cancel-Lock: sha1:ZnQHF5/X3bGs1DYqfN4Itr787bs= In-Reply-To: <cRRzT6nOqvNsNZkRCWbRl5usaUY@jntp> Content-Language: en-GB Bytes: 2394 Den 05.09.2024 16:15, skrev Richard Hachel: > Le 05/09/2024 à 14:24, "Paul.B.Andersen" a écrit : >> Den 05.09.2024 01:23, skrev Richard Hachel: >>> We KNOW that the travel time of A in A'B' will be equal to the distance A'B' in R' divided by the apparent escape velocity of an object moving at v=0.8c. >>> >>> Vo=0.8c >>> >>> Vapp=Vo/(1+cosµ.Vo/c) >>> >>> Vapp'=(4/9)c >>> >>> Vapp"=4c >>> >>> R.H. > What do you say, Paul? How confused is it possible to be? 😂 You must know that this 'apparent speed' is a visual observation (telescope). From whence did you get the idiotic idea that somebody is visually observing any of the clocks in this paper? https://paulba.no/pdf/Mutual_time_dilation.pdf A and B are moving with the speed v = 0.8c in K' <- A' and B' are moving with the speed v = 0.8c in K -> Nothing is moving with any other speed than v. There are no 'apparent speeds'. Is this too hard for you to understand? -- Paul https://paulba.no/