Deutsch English Français Italiano |
<vbfjlm$u3q4$1@dont-email.me> View for Bookmarking (what is this?) Look up another Usenet article |
Path: ...!news.mixmin.net!eternal-september.org!feeder3.eternal-september.org!news.eternal-september.org!.POSTED!not-for-mail From: "Paul.B.Andersen" <relativity@paulba.no> Newsgroups: sci.physics.relativity Subject: Re: Langevin and Doppler effects... Date: Fri, 6 Sep 2024 21:04:43 +0200 Organization: A noiseless patient Spider Lines: 88 Message-ID: <vbfjlm$u3q4$1@dont-email.me> References: <b5WDgbOwGmhfWpul72-1Pn3t5Ac@jntp> MIME-Version: 1.0 Content-Type: text/plain; charset=UTF-8; format=flowed Content-Transfer-Encoding: 8bit Injection-Date: Fri, 06 Sep 2024 21:03:18 +0200 (CEST) Injection-Info: dont-email.me; posting-host="046f4cbc334df1e771ab16fa22376136"; logging-data="986948"; mail-complaints-to="abuse@eternal-september.org"; posting-account="U2FsdGVkX18AqZF88q+iOKSlqou0UfPy" User-Agent: Mozilla Thunderbird Cancel-Lock: sha1:2/oWB/3FD+Aq9sB4Wty27sf7KNY= Content-Language: en-GB In-Reply-To: <b5WDgbOwGmhfWpul72-1Pn3t5Ac@jntp> Bytes: 3445 Den 05.09.2024 23:45, skrev Richard Hachel: > > Paul B. Andersen : > > https://paulba.no/pdf/TwinsByDoppler.pdf > > Well. > There are often few numerical applications in the > developments of relativistic theorists, because this can pose some > problems of contradiction, or even absurdity. > > We will return to the eternal problem, which has scared away all the > contributors I have dealt with for 40 years, although the opposite is > always said, and that I am the one who would be a wimp. > > So we return to the problem, which is nevertheless very simple. > > Stella goes into the stars for a journey of 24 light years. > > The speed is 0.8c on the way there (12 ly), and 0.8c on the way back (12 > ly). > > We quickly obtain the following data by the Doppler effect. > > Stella and Terrence agree to beep every month. You will find the answer here: https://paulba.no/pdf/TwinsByDoppler.pdf L = 12 ly c = 1 ly/y f = 12/y v = 0.8c γ = 5/3 But since you never read anything, I will repeat it here. > > It is clear that, for Stella, on the way there, as on the way back, she > will beep > 108 times (216 times in total). > > SO, Terrence will receive 216 beeps. OK. Stella has aged Tₛ = 2L/vγ = 18 y Number of received beeps Ns = Tₛ⋅f = 216 > > For his part, Terrence will beep for 30 years. He will therefore send > 360 beeps. OK > > Except that if Terrence receives the same number of beeps on the way > there as on the way back (108 each time), Stella receives many more > beeps on the way back than on the way there. > > It is then interesting to know how many beeps Stella receives on the way > there, and how many she receives on the way back. Doppler shift when Stella is moving out Do = √((c−v)/(c+v)) = 1/3 Doppler shift when Stella is moving back Db = √((c+v)/(c-v)) = 3 So number of received beeps Nt = Tₛ⋅f⋅Do/2 + Tₛ⋅f⋅Db/2 = 36 + 324 = 360 > > Once this is done, we can still progress in understanding things. > > We just have to not be afraid, and have a playful spirit. Terrence will age C = 2L/v = 30y Am I guessing wrong when I guess that you will present us with the paradox that Terrence will receive Tₜₛ⋅f⋅Do/2 + Tₜₛ⋅f⋅Db/2 = 60 + 540 = 600 beeps ? :-D Hint: https://paulba.no/pdf/TwinsByDoppler.pdf > > R.H. -- Paul https://paulba.no/