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Path: ...!eternal-september.org!feeder3.eternal-september.org!news.eternal-september.org!.POSTED!not-for-mail From: "Chris M. Thomasson" <chris.m.thomasson.1@gmail.com> Newsgroups: sci.math Subject: Re: What about normalized gaps? Date: Tue, 10 Sep 2024 14:11:56 -0700 Organization: A noiseless patient Spider Lines: 41 Message-ID: <vbqcms$35kea$1@dont-email.me> References: <vbqb4u$3527h$7@dont-email.me> MIME-Version: 1.0 Content-Type: text/plain; charset=UTF-8; format=flowed Content-Transfer-Encoding: 7bit Injection-Date: Tue, 10 Sep 2024 23:11:56 +0200 (CEST) Injection-Info: dont-email.me; posting-host="0eac113f4bd26321cfce58ecec11144e"; logging-data="3330506"; mail-complaints-to="abuse@eternal-september.org"; posting-account="U2FsdGVkX19i2LFgIzEjlO9fbB4SPPtGUkhU7jGCpiw=" User-Agent: Mozilla Thunderbird Cancel-Lock: sha1:Otf++Qar9xgWRDE3zpyt8QprGKM= In-Reply-To: <vbqb4u$3527h$7@dont-email.me> Content-Language: en-US Bytes: 1937 On 9/10/2024 1:45 PM, Chris M. Thomasson wrote: > To normalize the distance between two points in n-ary space. p0 and p1 > can be n-ary vectors. > > p0 = 1/2 > p1 = 1/1 > pdif = p1 - p0 > > the mid point would use the unit fraction 1/2 at: > > pmid = p0 + pdif * 1/2 > > right? > > For say a 3d vector of the above would be: > > p0 = (1/2, 0, 0) > p1 = (1/1, 0, 0) > > We can plot these. Say > > > p0 = (1/2, 1/4, 1/1) > p1 = (1/2, 1/3, -1/8) > > That is a line in pure 3d space, yet the line normalization still works. > The unit fraction 1/2 is half way in between p0 and p1... > > pdif = p1 - p0 > pmid = p0 + pdif * 1/2 > > Right? Wrt normalizing it where p0 + pdif * 0 = p0 and p0 + pdif * 1 = p1 allows us to use unit fractions to find points on the line from p0 to p1? For instance p2 would be 1/4 across from p0 to p1 where: p2 = p0 + pdif * 1/4 Draw a line from p0 to p2.