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From: "Keith F. Lynch" <kfl@KeithLynch.net>
Newsgroups: rec.puzzles,sci.lang
Subject: Re: Three rational triples
Date: Fri, 20 Sep 2024 00:07:29 -0000 (UTC)
Organization: United Individualist
Message-ID: <vciec1$1ia$1@reader1.panix.com>
References: <vbs1kg$9ad$1@reader1.panix.com> <vc07ik$lc2i$1@dont-email.me> <e9ba5f041858e8801883263284733779@www.novabbs.com> <90a25dad13a1ee6ee5e550d93bd72888@www.novabbs.com>
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HenHanna <HenHanna@dev.null> wrote:
> So this post below didn't get to your site (or Newsreader).
> IlanMayer wrote:
>> . . .
>> The sum of each triplet is the same as its product.
>>
>> 9/2*4/3*7/6 = 9/2+4/3+7/6 = 7
>> 49/15*25/21*54/35 = 49/15+25/21+54/35 = 6
>> 49/2*4/7*27/14 = 49/2+4/7+27/14 = 27
>>
>> Please reply to ilanlmayer at gmail dot com
>>
>>    __/\__
>>    \    /
>> __/\\  //\__  Ilan Mayer
>> \          /
>> /__      __\  Toronto, Canada
>>   /__  __\
>>      ||

Thanks for forwarding that.  I don't know why that post never showed
up on Panix.
-- 
Keith F. Lynch - http://keithlynch.net/
Please see http://keithlynch.net/email.html before emailing me.