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Path: ...!2.eu.feeder.erje.net!feeder.erje.net!eternal-september.org!feeder3.eternal-september.org!news.eternal-september.org!.POSTED!not-for-mail From: Lasse Langwadt <llc@fonz.dk> Newsgroups: sci.electronics.design Subject: Re: Power from another source fed to 1117 regulator output pin Date: Mon, 30 Sep 2024 19:51:37 +0200 Organization: A noiseless patient Spider Lines: 24 Message-ID: <vdeof9$2av9a$1@dont-email.me> References: <B3wKO.8728$ALMc.3588@fx01.ams1> <vde54a$27tr9$1@dont-email.me> <AOyKO.63936$l6I9.52273@fx13.ams1> MIME-Version: 1.0 Content-Type: text/plain; charset=UTF-8; format=flowed Content-Transfer-Encoding: 7bit Injection-Date: Mon, 30 Sep 2024 19:51:37 +0200 (CEST) Injection-Info: dont-email.me; posting-host="6bb9ec94ee4e1c679b2d5526410c58f0"; logging-data="2456874"; mail-complaints-to="abuse@eternal-september.org"; posting-account="U2FsdGVkX1/U+EFX3Ql8NHiASbRr+8BQEoxShiIIBuc=" User-Agent: Mozilla Thunderbird Cancel-Lock: sha1:jefjCJPTefvuuo0gGMT7zF2DQSU= Content-Language: en-US In-Reply-To: <AOyKO.63936$l6I9.52273@fx13.ams1> Bytes: 2330 On 9/30/24 16:43, Pimpom wrote: > On 30-09-2024 05:51 pm, Don Y wrote: >> On 9/30/2024 4:37 AM, Pimpom wrote: >>> I've been looking at the schematic of a popular product that has two >>> options as the power source. One source is a Vin point (pin or DC >>> jack) that goes to a 1117-5V regulator, the other is a USB port. The >>> USB +5V line joins the 1117 output via a Schottky diode. >>> >>> Does this mean that the 1117 has no problem with this arrangement - >>> that is, with power coming from another source to its output pin? >> >> Short the LDO's input to GND and consider how it will (mis)behave. >> > Sure, this issue is often brought up while discussing regulators. > Apparently the makers of the product (Arduino, various versions) seem to > feel that the input of the LDO getting shorted while being powered via > USB is not likely enough to bother with. > > Anyway, what I'm thinking about is how the LDO's internal circuit reacts > to being reverse fed a voltage at the output pin without having an input > but *without* the input being shorted to ground. then the input will equalize to the output voltage and no current will flow and nothing happens