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From: "Steven G. Kargl" <sgk@REMOVEtroutmask.apl.washington.edu>
Newsgroups: comp.lang.fortran
Subject: Re: Is there a way in Fortran to designate an integer value as
 integer*8 ?
Date: Thu, 3 Oct 2024 04:27:31 -0000 (UTC)
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On Wed, 02 Oct 2024 14:30:48 -0500, Lynn McGuire wrote:

> On 10/2/2024 2:00 AM, Lawrence D'Oliveiro wrote:
>> On Tue, 1 Oct 2024 21:58:40 -0500, Lynn McGuire wrote:
>> 
>>> I need many of my integers to be integer*8 in my port to 64 bit.  In
>>> C/C++ code, I can say 123456L to mean a long long value, generally 64
>>> bit.  Is there a corresponding way to do this in Fortran ...
>> 
>>      integer(kind = 8), parameter :: bigval = 9223372036854775807_8
>>      print *, bigval
>> 
>> prints
>> 
>>      9223372036854775807
> 
> Thanks !
> 
> I was afraid of that.  I will have to put _8 in about 100,000 lines of 
> my F77 code.  And the future conversion to C++ will need special handling.
> 

If you 100,000 lines of C++ without a trailing 'L', you would
need to add 'L' to get a long int.  You also only need to add
'_8' (or 'L') to those values that would exceed huge(1) in
magnitude as integer*4 is a proper subset of integer*8 and
Fortran does conversion when required.

-- 
steve