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Path: ...!2.eu.feeder.erje.net!3.eu.feeder.erje.net!feeder.erje.net!eternal-september.org!feeder3.eternal-september.org!news.eternal-september.org!.POSTED!not-for-mail From: "Paul.B.Andersen" <relativity@paulba.no> Newsgroups: sci.physics.relativity Subject: =?UTF-8?Q?Re=3A_I_dare_to_relativists_to_explain_local_time=3A_t-vx?= =?UTF-8?Q?/c=C2=B2?= Date: Sat, 5 Oct 2024 22:11:32 +0200 Organization: A noiseless patient Spider Lines: 92 Message-ID: <vds6da$sl6n$1@dont-email.me> References: <8dc9a6eb5ee097da5239175cb7833cd6@www.novabbs.com> <ebCdnU-bKuOJYmD7nZ2dnZfqnPGdnZ2d@giganews.com> <6a64a60eb15efe9a5449ade234d05804@www.novabbs.com> <fc3e047c7de75fd713b8844393a5234e@www.novabbs.com> MIME-Version: 1.0 Content-Type: text/plain; charset=UTF-8; format=flowed Content-Transfer-Encoding: 8bit Injection-Date: Sat, 05 Oct 2024 22:09:15 +0200 (CEST) Injection-Info: dont-email.me; posting-host="e536b49a861ecd6fc0538e1a2a6ecd44"; logging-data="939223"; mail-complaints-to="abuse@eternal-september.org"; posting-account="U2FsdGVkX1+qCYhcTTpVipdKHC0WRZxw" User-Agent: Mozilla Thunderbird Cancel-Lock: sha1:wtc51Aai+stR2GcE4h7+PnCU1RU= Content-Language: en-GB In-Reply-To: <fc3e047c7de75fd713b8844393a5234e@www.novabbs.com> Bytes: 3332 Den 05.10.2024 19:32, skrev rhertz: > Explain this: > > 1905 EINSTEIN'S MODIFIED LORENTZ TRANSFORMS > t' = γ (t - vx/c²) > x' = γ (x - vt) > > IF > > v = 11 Km/sec > x = 400 Km > > γ = 1.00000000067222 γ = 1.00000000067315 ≈ 1.000000000673 > > > t' ≈ t - 48.89 nsec wrong, see below > > 48.89 nanoseconds meaning WHAT? That your calculation is wrong. You do know that the Lorentz transform is a coordinate transformation, or don't you? If the coordinates of an event are x = 400 km, t = t seconds in the un-primed frame, then the coordinates of the event in the primed frame are: t' = (1.00000000067315⋅t - 48.96e-9) second x' = (400000.0002692 - 11000.0000074⋅t) meter Note that t is a number you failed to define. > > > > Worse yet. Is anything bad? > > IF x' = 0, then x = vt > > t' = γ (t - vx/c²) = γ (t - v²/c² t) = t/γ Or generally: if x' is constant then dt'/dt = 1/γ if x is constant then dt/dt' = 1/γ A clock which is stationary in a frame of reference will be measured to run slow in a frame of reference which is moving relative to the clock. > > t' = 0.999999998655556 t (now t' run slower than t!) Yes, because the clock is stationary in the primed frame. See: https://paulba.no/pdf/Mutual_time_dilation.pdf > > Any explanations about these numerical examples of > the ridiculous results when applying SR? There are no ridiculous results. That Richard Hertz finds SR to be ridiculous doesn't change the fact that SR is thoroughly experimentally tested and never is falsified. Some of the experimental evidence: https://paulba.no/paper/index.html That Richard Hertz find SR to be ridiculous does however have the consequence that he has to claim that all physicist born after 1900 are frauds and member of a MAFFIA. If they were not, Richard Hertz would be wrong, which according to Richard Hertz is impossible. Hilarious, no? :-D -- Paul https://paulba.no/