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From: olcott <polcott333@gmail.com>
Newsgroups: comp.theory
Subject: Re: Even Google AI Overview understands me now --- different
 execution traces have different behavior !!!
Date: Sun, 6 Oct 2024 07:43:50 -0500
Organization: A noiseless patient Spider
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On 10/6/2024 6:13 AM, Richard Damon wrote:
> On 10/5/24 11:54 PM, olcott wrote:
>> On 10/5/2024 10:51 PM, Richard Damon wrote:
>>> On 10/5/24 11:39 PM, olcott wrote:
>>>> On 10/5/2024 10:22 PM, Richard Damon wrote:
>>>>> On 10/5/24 10:58 PM, olcott wrote:
>>>>>> On 10/5/2024 9:46 PM, Richard Damon wrote:
>>>>>>> On 10/5/24 9:43 AM, olcott wrote:
>>>>>>>> On 10/5/2024 8:38 AM, Richard Damon wrote:
>>>>>>>>> On 10/5/24 9:34 AM, olcott wrote:
>>>>>>>>>> On 10/5/2024 8:27 AM, Richard Damon wrote:
>>>>>>>>>>> On 10/5/24 8:21 AM, olcott wrote:
>>>>>>>>>>>> On 10/5/2024 5:58 AM, Richard Damon wrote:
>>>>>>>>>>>>> On 10/4/24 9:53 PM, olcott wrote:
>>>>>>>>>>>>
>>>>>>>>>>>> That you are unable to understand that it is easily 
>>>>>>>>>>>> conclusively
>>>>>>>>>>>> proven (below) that the emulated HHH does emulate its DDD 
>>>>>>>>>>>> correctly
>>>>>>>>>>>> is why your double-talk gibberish rebuttal fails.
>>>>>>>>>>>>
>>>>>>>>>>>
>>>>>>>>>>> Nope, the trace actually proves the opposite.
>>>>>>>>>>>
>>>>>>>>>>
>>>>>>>>>> The following execution trace conclusively proves that
>>>>>>>>>> HHH emulated by itself does emulate the first four lines
>>>>>>>>>> of DDD correctly.
>>>>>>>>>
>>>>>>>>> Right, and then makes the error of PRESUMEING INCORREDTLY that 
>>>>>>>>> HHH(DDD) will not return,
>>>>>>>>
>>>>>>>> That this is over-your-head really is not my mistake.
>>>>>>>> *DDD emulated by HHH cannot possibly return*
>>>>>>>
>>>>>>> No, it is beyond YOUR head that the fact that HHH does abort its 
>>>>>>> emulation means its doesn't show if the HHH that it was emulating 
>>>>>>> will return on not.
>>>>>>>
>>>>>>
>>>>>> This is simply over your head.
>>>>>> The infinite set of DDD emulated by HHH
>>>>>> never returns no matter what its corresponding HHH does.
>>>>>
>>>>> No, that is just a false statement based on you changing the 
>>>>> meaning of the words.
>>>>>
>>>>> EVERY DDD that calls an HHH(DDD) that ever returns an answer will 
>>>>> halt.
>>>>>
>>>>
>>>> No DDD emulated by any corresponding HHH ever returns
>>>> and the HHH that emulates it does return an answer
>>>> corresponding to this behavior of this emulated DDD.
>>>>
>>>
>>> That is a lie based on your misunderstanding of the meaning of the 
>>> words.
>>>
>>
>> *No DDD emulated by any corresponding HHH ever returns*
>> Until you understand this point you remain clueless.
>>
>>
> 
> Which is just a LIE as I explained.
> 
> If HHH(DDD) returns 0, as your claimed correct one does, then DDD will 
> return and that answer is wrong.
> 

I have proven that you are factually incorrect. This is
simply over-your-head. You seem to have the fallacy of
equivocation error in your reasoning. You might not even
know what that is. You may look it up and still not know
what that is.

DDD emulated by each corresponding HHH that can possibly
exist never returns. Each of these HHH emulators that does
return 0 correctly reports the above non-halting behavior.


-- 
Copyright 2024 Olcott "Talent hits a target no one else can hit; Genius
hits a target no one else can see." Arthur Schopenhauer