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From: olcott <polcott333@gmail.com>
Newsgroups: comp.theory
Subject: Re: Simulating Termination Analyzer HHH correctly rejects input DDD
Date: Wed, 9 Oct 2024 13:46:22 -0500
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On 10/9/2024 6:46 AM, Richard Damon wrote:
> On 10/9/24 7:01 AM, olcott wrote:
>> On 10/9/2024 1:08 AM, Jeff Barnett wrote:
>>> On 10/8/2024 6:49 AM, Andy Walker wrote:
>>>> ... after a short break.
>>>>
>>>>      Richard -- no-one sane carries on an extended discussion with
>>>> someone they [claim to] consider a "stupid liar".  So which are you?
>>>> Not sane?  Or stupid enough to try to score points off someone who is
>>>> incapable of conceding them?  Or lying when you describe Peter?  You
>>>> must surely have better things to do.  Meanwhile, you surely noticed
>>>> that Peter is running rings around you.
>>>>
>>>>      Peter -- you surely have better things to do.  No-one sensible
>>>> is reading the repetitive stuff.  Decades, and myriads of articles, ago
>>>> people here tried to help you knock your points into shape, but 
>>>> anything
>>>> sensible is swamped by the insults.  Free advice, worth roughly what 
>>>> you
>>>> are paying for it:  step back, and summarise [from scratch, not 
>>>> using HHH
>>>> and DDD (etc) without explanation] (a) what it is you think you are 
>>>> trying
>>>> to prove and (b) what progress you claim to have made.  No more than 
>>>> one
>>>> side of paper.  Assume that people who don't actively insult you 
>>>> are, in
>>>> fact, trying to help.
>>>
>>> And this approach has been tried many times. It makes no more 
>>> progress than the ones you are criticizing. Just assume the regulars 
>>> are lonesome, very lonesome and USENET keeps everybody off the 
>>> deserted streets at night.
>>
>> HHH is an emulating termination analyzer that takes the machine
>> address of DDD as input then emulates the x86 machine language
>> of DDD until a non-terminating behavior pattern is recognized.
> 
> But fails, because you provided it with a proven incorrect pattern
> 
>>
>> HHH recognizes this pattern when HHH emulates itself emulating DDD
>>
>> void DDD()
>> {
>>    HHH(DDD);
>>    return;
>> }
>>
> 
> Which isn't a correct analysis (but of course, that is just what you do)
> 
> Since we know that HHH(DDD) returns 0, it can not be a non-terminating 
> behaivor, but that claim is just a lie.
> 
>> One cannot simply ignore the actual behavior specified by the
>> finite string x86 machine language of DDD such that
>>
> 
> Right, one can not ignore the fact that HHH(DDD) is determined to return 0.
> 
>> DDD emulated by each corresponding HHH that can possibly
>> exist never returns
> 
> More lies. It has been determined that EVERY DDD that calls an HHH(DDD) 
> that returns 0 will halt.
> 
> The DDDs that don't return are the ones that call an HHH that never 
> returns an answer.
> 

*Your weasel words are in incorrect paraphrase of this*

DDD emulated by each corresponding HHH that can possibly
exist never returns

thus each of the directly executed HHH emulators that does
return 0 correctly reports the above non-terminating behavior.


-- 
Copyright 2024 Olcott "Talent hits a target no one else can hit; Genius
hits a target no one else can see." Arthur Schopenhauer