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From: Mikko <mikko.levanto@iki.fi>
Newsgroups: comp.theory
Subject: Re: The philosophy of computation reformulates existing ideas on a new basis
Date: Thu, 7 Nov 2024 11:56:54 +0200
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On 2024-11-06 15:26:06 +0000, olcott said:
> On 11/6/2024 8:39 AM, Mikko wrote:
>> On 2024-11-05 13:18:43 +0000, olcott said:
>>
>>> On 11/5/2024 3:01 AM, Mikko wrote:
>>>> On 2024-11-03 15:13:56 +0000, olcott said:
>>>>
>>>>> On 11/3/2024 7:04 AM, Mikko wrote:
>>>>>> On 2024-11-02 12:24:29 +0000, olcott said:
>>>>>>
>>>>>>> HHH does compute the mapping from its input DDD
>>>>>>> to the actual behavior that DDD specifies and this
>>>>>>> DOES INCLUDE HHH emulating itself emulating DDD.
>>>>>>
>>>>>> Yes but not the particular mapping required by the halting problem.
>>>>>
>>>>> Yes it is the particular mapping required by the halting problem.
>>>>> The exact same process occurs in the Linz proof.
>>>>
>>>> The halting probelm requires that every halt decider terminates.
>>>> If HHH(DDD) terminates so does DDD. The halting problmen requires
>>>> that if DDD terminates then HHH(DDD) accepts as halting.
>>>
>>> void Infinite_Loop()
>>> {
>>> HERE: goto HERE;
>>> return;
>>> }
>>>
>>> No that is false.
>>> The measure is whether a C function can possibly
>>> reach its "return" instruction final state.
>>
>> Not in the original problem but the question whether a particular strictly
>> C function will ever reach its return instruction is equally hard. About
>
> It has always been about whether or not a finite string input
> specifies a computation that reaches its final state.
Not really. The original problem was not a halting problem but Turing's
solution was so easily adapted to the halting problem that we can say
that Turing solved the halting problem before nobody had presented it.
Turings original problem was to find a method to determine whether the
given Turing machine with given input ceases to write unerasable symbols.
Modern Turing machines don't even start as any symbol can be erased or
overwritten.
--
Mikko