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From: kurtz le pirate <kurtzlepirate@free.fr>
Newsgroups: fr.sci.maths
Subject: Puissaces et logarithmes
Date: Fri, 8 Nov 2024 11:17:06 +0100
Organization: compagnie de la banquise
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Hello,


Un truc qui me tarabuste et que je n'arrive pas à calculer formellement.


2^(log(3)/log(2)) = 3 = 3^1

4^(log(3)/log(2)) = 9 = 3^2

8^(log(3)/log(2)) = 27 = 3^3

....

a^(log(3)/log(2)) = 3^???




Si vous avez une piste.
Merci




-- 
kurtz le pirate
compagnie de la banquise