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From: cross@spitfire.i.gajendra.net (Dan Cross)
Newsgroups: comp.unix.programmer
Subject: Re: Command Languages Versus Programming Languages
Date: Fri, 22 Nov 2024 23:06:18 -0000 (UTC)
Organization: PANIX Public Access Internet and UNIX, NYC
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References: <uu54la$3su5b$6@dont-email.me> <87h67zrtns.fsf@doppelsaurus.mobileactivedefense.com> <vhqkm6$7dv$1@reader2.panix.com> <vhr0fj$1bq0o$1@dont-email.me>
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In article <vhr0fj$1bq0o$1@dont-email.me>,
James Kuyper  <jameskuyper@alumni.caltech.edu> wrote:
>On 11/22/24 14:05, Dan Cross wrote:
>> In article <87h67zrtns.fsf@doppelsaurus.mobileactivedefense.com>,
>> Rainer Weikusat <rweikusat@talktalk.net> wrote:...
>>> char **argv
>>>
>>> declares an array of pointers
>>
>> No, it declares a pointer to a pointer to char.
>
>Agreed.
>
>>> (as each pointer in C points to an array)
>>
>> That's absolutely not true. A pointer in C may refer to
>> an array, or a scalar. Consider,
>>
>> char c;
>> char *p = &c;
>> char **pp = &p;
>
>Not actually relevant. For purposes of pointer arithmetic, a pointer to
>a single object is treated as if it pointed at the first element of a
>1-element array of that object's type.

a) Please stop emailing me this stuff _and_ posting it here.  I
have asked you this in the past, and previously you'd said that
it was because you switched news readers.  That's fine, but that
was a year ago or more.

b) What you are referring to, from the section on Additive
Operators (6.5.7 in n3220; 6.5.6 in C99) is in reference to
pointer arithmetic; the statement that I was replying to was a
general statement about pointers, independent of issues of
pointer arithmetic.  That is, it is not the case that, "each
pointer in C points to an array".  The above example, to which
you replied, is a counterpoint to the general statement.

So while what you are saying is true, it doesn't change the
general point.

	- Dan C.