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From: WM <wolfgang.mueckenheim@tha.de>
Newsgroups: sci.math
Subject: Re: Incompleteness of Cantor's enumeration of the rational numbers
 (extra-ordinary)
Date: Thu, 28 Nov 2024 18:09:16 +0100
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On 28.11.2024 17:45, joes wrote:
> Am Thu, 28 Nov 2024 11:39:05 +0100 schrieb WM:

>> A simpler arguments is this: All endsegments are in a decreasing
>> sequence.
> There is no decrease, they are all infinite.

Every endsegment has one number less than its predecessor.
That is called decrease.
> 
>> Before the decrease has reached finite endsegments, all are
>> infinite and share an infinite contents from E(1) = ℕ on. They have not
>> yet had the chance to reduce their infinite subset below infinity.
> All segments are infinite. Nothing can come "afterwards".

Then never the intersection is never empty.

Regards, WM
>