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Path: ...!eternal-september.org!feeder3.eternal-september.org!news.eternal-september.org!.POSTED!not-for-mail
From: olcott <polcott333@gmail.com>
Newsgroups: comp.theory,sci.logic,comp.lang.c,comp.lang.c++
Subject: This first time anyone In the entire history of the halting problem
 derived a correct return value for HHH(DD)
Date: Wed, 4 Dec 2024 22:20:50 -0600
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There is an 80% chance that I will be alive in one month.
There may be an extended pause in my comments.
I will try to bring a computer to the out of town hospital.

On 12/4/2024 8:16 PM, Richard Damon wrote:
> On 12/4/24 8:50 PM, olcott wrote:
>> On 12/4/2024 7:45 PM, Richard Damon wrote:
>>> On 12/4/24 8:41 PM, olcott wrote:
>>>> On 12/4/2024 7:31 PM, Richard Damon wrote:
>>>>> On 12/4/24 8:06 PM, olcott wrote:
>>>>>> On 12/4/2024 6:11 PM, Richard Damon wrote:
>>>>>>> On 12/4/24 9:27 AM, olcott wrote:
>>>>>>>> On 12/3/2024 5:39 PM, Richard Damon wrote:
>>>>>>>>> On 12/3/24 6:08 PM, olcott wrote:
>>>>>>>>>> On 12/3/2024 3:03 AM, joes wrote:
>>>>>>>>>>> Am Mon, 02 Dec 2024 20:48:49 -0600 schrieb olcott:
>>>>>>>>>>>> On 11/28/2024 1:48 PM, joes wrote:
>>>>>>>>>
>>>>>>>>>>>> You said:
>>>>>>>>>>>>   >>> HHH can't simulate itself.
>>>>>>>>>>>> That is WRONG !!!
>>>>>>>>>>>> HHH DOES EMULATE ITSELF PROVING THAT IT CAN EMULATE ITSELF.
>>>>>>>>>>> We know that HHH halts. It doesn't simulate itself halting.
>>>>>>>>>>>
>>>>>>>>>>
>>>>>>>>>> Please try and explain how you are not dishonest what you
>>>>>>>>>> try to change the subject from my rebuttal of your statement:
>>>>>>>>>>
>>>>>>>>>>  >>> HHH can't simulate itself.
>>>>>>>>>>
>>>>>>>>>> That HHH does emulate itself emulating DDD proves
>>>>>>>>>> THAT IT CAN DO THIS.
>>>>>>>>>>
>>>>>>>>>
>>>>>>>>> But only if your think that wrong answer can be right.
>>>>>>>>
>>>>>>>> I did not mention anything about answers my entire
>>>>>>>> scope is that HHH does emulate itself emulating DDD
>>>>>>>> thus conclusively proving that HHH can emulated itself
>>>>>>>> emulating DDD.
>>>>>>>>
>>>>>>>> Whenever you go out-of-scope like this it surely
>>>>>>>> seems dishonest to me.
>>>>>>>>
>>>>>>>
>>>>>>> But the behaivor that HHH shows that it has *IS* an "answer",
>>>>>>
>>>>>> DDD emulated by any HHH according to the semantics of
>>>>>> the x86 language cannot possibly reach its "ret" instruction
>>>>>> whether HHH aborts this emulation after N steps or never aborts.
>>>>>>
>>>>>>
>>>>>
>>>>> Just a nonsense sentence, since HHH can't emulate HHH as it isn't 
>>>>> given it, 
>>>>
>>>> Why do you have to keep fucking lying about this?
>>>> I could die on the operating table in two weeks!
>>>>
>>>
>>> What's the lie?
>>>
>>> Can you point to what I say that is wrong, and a reliable reference 
>>> that show it?
>>>
>>> All you have is your own lies to call it a lie.
>>>
>>> And yes, you might die in two weeks, and the only thing you will have 
>>> left behind is all your lies.
>>
>> Yes you fucking jackass this conclusively proves that
>> HHH does emulate itself emulating DDD.
>>
>> https://github.com/plolcott/x86utm/blob/master/Halt7.c
>>
>>
> 
> Nope.
> 
> It proves that your HHH fails to meet its requirement to be pure 
> function 

It proves that HHH does emulate itself emulating DDD.

Once we get through this point then we know that DDD
does not halt:

DDD emulated by any HHH according to the semantics of
the x86 language cannot possibly reach its "ret" instruction
whether HHH aborts this emulation after N steps or never aborts.
*This tells us that DDD emulated by HHH DOES NOT HALT*

We do not begin to examine whether or not HHH found this
answer as a pure function until after we agree with the
prior point.

*In all of the history of the halting problem there*
*have never been a correct return value for this*

typedef void (*ptr)();
int HHH(ptr P);

int DD()
{
   int Halt_Status = HHH(DD);
   if (Halt_Status)
     HERE: goto HERE;
   return Halt_Status;
}

int main()
{
   HHH(DD);
}

When we understand that the first point is correct
then we know that HHH returning 0 is correct.
*This has much has never ever been done before*

Then after we know that HHH(DD) is correct to return
0 for its input we get to applying Mike's idea to
make HHH a pure function.

Simulating Termination Analyzer H is Not Fooled by Pathological Input D
https://www.researchgate.net/publication/369971402_Simulating_Termination_Analyzer_H_is_Not_Fooled_by_Pathological_Input_D 


// Entire x86utm operating system that emulates Halt7.obj
https://github.com/plolcott/x86utm

// source code of termination analyzers and their sample input
https://github.com/plolcott/x86utm/blob/master/Halt7.c

x86utm.sln   in visual studio
__Run_7.bat  on the command line

-- 
Copyright 2024 Olcott "Talent hits a target no one else can hit; Genius
hits a target no one else can see." Arthur Schopenhauer