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From: FromTheRafters <FTR@nomail.afraid.org>
Newsgroups: sci.math
Subject: Re: Incompleteness of Cantor's enumeration of the rational numbers (extra-ordinary)
Date: Thu, 05 Dec 2024 17:29:29 -0500
Organization: Peripheral Visions
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References: <vg7cp8$9jka$1@dont-email.me> <vier32$1madr$1@dont-email.me> <vierv5$1l1ot$2@dont-email.me> <viiqfd$2qq41$5@dont-email.me> <vijhrd$34mp8$1@dont-email.me> <vilh59$3k21l$5@dont-email.me> <vilheq$3ks01$3@dont-email.me> <vilhjk$3k21l$9@dont-email.me> <vilhk8$3ks01$4@dont-email.me> <vilhnl$3k21l$10@dont-email.me> <viljdo$3k21l$12@dont-email.me> <87frn50zjp.fsf@bsb.me.uk> <vinuvc$cdlu$1@dont-email.me> <vinvvu$c7p5$6@dont-email.me> <vio0u4$c7p5$8@dont-email.me> <vio8rj$ei97$5@dont-email.me> <vio9nu$f13q$1@dont-email.me> <vip1f1$npsr$2@dont-email.me> <vipaue$qd3r$1@dont-email.me> <87y10vzo35.fsf@bsb.me.uk> <vipf6v$qr8p$2@dont-email.me> <87ser3zgez.fsf@bsb.me.uk> <viqca6$12cut$2@dont-email.me> <virpnj$1g4uq$1@dont-email.me> <ff5ee533dd180eb24978c76e7e00ba6f4676d51a@i2pn2.org> <vis3iq$1iu5p$1@dont-email.me> <visafv$1kq6a$1@dont-email.me> <visi6v$1mmrh$1@dont-email.me> <vislkd$1nn4k$1@dont-email.me> <visune$1pp27$1@dont-email.me>
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WM presented the following explanation :
> On 05.12.2024 17:50, FromTheRafters wrote:
>> WM pretended :
>>> On 05.12.2024 14:40, FromTheRafters wrote:
>>>> WM used his keyboard to write :
>>>
>>>>> All means all with no exception. But every number you can take belongs 
>>>>> to a vanishing subset of ℕ.
>>>>
>>>> What do you mean by vanishing?
>>>
>>> The subset of numbers that can be taken is ℕ_def. It is smaller than
>>> |ℕ|/k for every k ∈ ℕ.
>>>
>>> Have you meanwhile found an example for sequences with terms a_n = b_n for 
>>> every n but different limit?
>> 
>> Why should I?
>
> Your answer to Identical sequences have the same limit: "Running with 
> buffaloes does not make one a buffalo" appeared to doubt my claim.

Your example ignores the step-by-step dwindling aspect of the 
intersections of your infinite sequence of endsegments. It walks like a 
McDuck and talks like a McDuck.