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From: WM <wolfgang.mueckenheim@tha.de>
Newsgroups: sci.math
Subject: Re: Incompleteness of Cantor's enumeration of the rational numbers
 (extra-ordinary)
Date: Fri, 6 Dec 2024 09:59:22 +0100
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On 05.12.2024 23:29, FromTheRafters wrote:
> WM presented the following explanation :

>> Your answer to Identical sequences have the same limit: "Running with 
>> buffaloes does not make one a buffalo" appeared to doubt my claim.
> 
> Your example ignores the step-by-step dwindling aspect of the 
> intersections of your infinite sequence of endsegments.

No, it uses this dwindling in endsegments and intersections.
∀n ∈ ℕ: E(1)∩E(2)∩...∩E(n) = E(n)
Identical sequences have identical limits.

Regards, WM