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From: WM <wolfgang.mueckenheim@tha.de>
Newsgroups: sci.math
Subject: Re: Incompleteness of Cantor's enumeration of the rational numbers
 (extra-ordinary)
Date: Mon, 16 Dec 2024 09:30:18 +0100
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On 15.12.2024 21:21, joes wrote:
> Am Sun, 15 Dec 2024 16:25:55 +0100 schrieb WM:
>> On 15.12.2024 12:15, joes wrote:
>>> Am Sat, 14 Dec 2024 17:00:43 +0100 schrieb WM:
>>
>>>>>>>> That pairs the elements of D with the elements of ℕ. Alas, it can
>>>>>>>> be proved that for every interval [1, n] the deficit of hats
>>>>>>>> amounts to at least 90 %. And beyond all n, there are no further
>>>>>>>> hats.
>>>>>>> But we aren't dealing with intervals of [1, n] but of the full set.
>>>>>> Those who try to forbid the detailed analysis are dishonest
>>>>>> swindlers and tricksters and not worth to participate in scientific
>>>>>> discussion.
>>>>> No, we are not forbiding "detailed" analysis
>>>> Then deal with all infinitely many intervals [1, n].
>>> ??? The bijection is not finite.
>> Therefore we use all [1, n].
> Those are all finite.

All n are finite.
> 
>>>>>>> The problem is that you can't GET to "beyond all n" in the pairing,
>>>>>>> as there are always more n to get to.
>>>>>> If this is impossible, then also Cantor cannot use all n.
>>>>> Why can't he? The problem is in the space of the full set, not the
>>>>> finite sub sets.
>>>> The intervals [1, n] cover the full set.
>>> Only in the limit.
>> With and without limit.
> Wonrg. There is no natural n that „covers N”.

All intervals do it because there is no n outside of all intervals [1, 
n]. My proof applies all intervals.

Regards, WM