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From: WM <wolfgang.mueckenheim@tha.de>
Newsgroups: sci.math
Subject: Re: Incompleteness of Cantor's enumeration of the rational numbers
 (extra-ordinary)
Date: Thu, 26 Dec 2024 18:18:11 +0100
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On 26.12.2024 13:55, Richard Damon wrote:
> On 12/26/24 6:36 AM, WM wrote:
>> On 24.12.2024 15:06, Richard Damon wrote:
>>> On 12/24/24 5:45 AM, WM wrote:
>>>> On 23.12.2024 15:32, Richard Damon wrote:
>>>>> On 12/23/24 4:31 AM, WM wrote:
>>>>
>>>>>>>> No, I do as Cantor did.
>>>>>>
>>>>>>> No, you do what you THINK Cantor did,
>>>>>>
>>>>>> Show an n that I do not use with all intervals [1, n].
>>>>
>>>>> The LAST one, which you say must exist to use your logic.
>>>>
>>>> I do what Cantor did. There is no last one. You cannot show an n 
>>>> that I do not use. There is none. Therefore all your arguing breaks 
>>>> down.
>>>>
>>> No, you do NOT do what Cantor did,
>>
>> What n do I not use?
>>
> The LAST one, that completes the set.

Cantor misses it. Therefore I do not use it either.

> The fact that after any finite number of removals, there are still 
> elements does not mean that when you remove *ALL* the elements there 
> will still be some left.#

This fact shows that "all" cannot be removed individually. They can only 
be removed collectively. Proof of dark numbers.

Regards, WM