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From: olcott <polcott333@gmail.com>
Newsgroups: comp.theory
Subject: Re: Anyone with sufficient knowledge of C knows that DD specifies
 non-terminating behavior to HHH
Date: Fri, 21 Feb 2025 16:35:16 -0600
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On 2/21/2025 2:18 AM, Mikko wrote:
> On 2025-02-20 21:31:44 +0000, olcott said:
> 
>> On 2/20/2025 2:38 AM, Mikko wrote:
>>> On 2025-02-20 00:31:33 +0000, olcott said:
>>>
>>>> On 2/19/2025 3:01 AM, Mikko wrote:
>>>>> On 2025-02-18 11:26:25 +0000, olcott said:
>>>>>
>>>>>> On 2/18/2025 3:24 AM, Mikko wrote:
>>>>>>> On 2025-02-17 09:05:42 +0000, Fred. Zwarts said:
>>>>>>>
>>>>>>>> Op 16.feb.2025 om 23:51 schreef olcott:
>>>>>>>>> On 2/16/2025 4:30 PM, joes wrote:
>>>>>>>>>> Am Sun, 16 Feb 2025 15:58:14 -0600 schrieb olcott:
>>>>>>>>>>> On 2/16/2025 2:02 PM, joes wrote:
>>>>>>>>>>>> Am Sun, 16 Feb 2025 13:24:14 -0600 schrieb olcott:
>>>>>>>>>>>>> On 2/16/2025 10:35 AM, joes wrote:
>>>>>>>>>>>>>> Am Sun, 16 Feb 2025 06:51:12 -0600 schrieb olcott:
>>>>>>>>>>>>>>> On 2/15/2025 2:49 AM, Mikko wrote:
>>>>>>>>>>>>>>>> On 2025-02-14 12:40:04 +0000, olcott said:
>>>>>>>>>>>>>>>>> On 2/14/2025 2:58 AM, Mikko wrote:
>>>>>>>>>>>>>>>>>> On 2025-02-14 00:07:23 +0000, olcott said:
>>>>>>>>>>>>>>>>>>> On 2/13/2025 3:20 AM, Mikko wrote:
>>>>>>>>>>>>>>>>>>>> On 2025-02-13 04:21:34 +0000, olcott said:
>>>>>>>>>>>>>>>>>>>>> On 2/12/2025 4:04 AM, Mikko wrote:
>>>>>>>>>>>>>>>>>>>>>> On 2025-02-11 14:41:38 +0000, olcott said:
>>>>>>>>>>
>>>>>>>>>>>>>>>>> DD  correctly simulated by HHH cannot possibly 
>>>>>>>>>>>>>>>>> terminate normally.
>>>>>>>>>>>>>>>>
>>>>>>>>>>>>>>>> That claim has already shown to be false. Nothing above 
>>>>>>>>>>>>>>>> shows that
>>>>>>>>>>>>>>>> HHH does not return 0. If it does DD also returns 0.
>>>>>>>>>>>>>>> When we are referring to the above DD simulated by HHH 
>>>>>>>>>>>>>>> and not
>>>>>>>>>>>>>>> trying to get away with changing the subject to some 
>>>>>>>>>>>>>>> other DD
>>>>>>>>>>>>>>> somewhere else
>>>>>>>>>>>>>> such as one that calls a non-aborting version of HHH
>>>>>>>>>>>>>>
>>>>>>>>>>>>>>> then anyone with sufficient knowledge of C programming 
>>>>>>>>>>>>>>> knows that no
>>>>>>>>>>>>>>> instance of DD shown above simulated by any corresponding 
>>>>>>>>>>>>>>> instance
>>>>>>>>>>>>>>> of HHH can possibly terminate normally.
>>>>>>>>>>>>>> Well, then that corresponding (by what?) HHH isn’t a decider.
>>>>>>>>>>>>> I am focusing on the isomorphic notion of a termination 
>>>>>>>>>>>>> analyzer.
>>>>>>>>>>>> (There are other deciders that are not termination analysers.)
>>>>>>>>>>>>
>>>>>>>>>>>>> A simulating termination analyzer correctly rejects any 
>>>>>>>>>>>>> input that
>>>>>>>>>>>>> must be aborted to prevent its own non-termination.
>>>>>>>>>>>> Yes, in particular itself is not such an input, because we 
>>>>>>>>>>>> *know* that
>>>>>>>>>>>> it halts, because it is a decider. You can’t have your cake 
>>>>>>>>>>>> and eat it
>>>>>>>>>>>> too.
>>>>>>>>>>> I am not even using the confusing term "halts".
>>>>>>>>>>> Instead I am using in its place "terminates normally".
>>>>>>>>>>> DD correctly simulated by HHH cannot possibly terminate 
>>>>>>>>>>> normally.
>>>>>>>>>> What’s confusing about „halts”? I find it clearer as it does 
>>>>>>>>>> not imply
>>>>>>>>>> an ambiguous „abnormal termination”. How does HHH simulate DD
>>>>>>>>>> terminating abnormally, then? Why doesn’t it terminate abnormally
>>>>>>>>>> itself?
>>>>>>>>>> You can substitute the term: the input DD to HHH does not need 
>>>>>>>>>> to be
>>>>>>>>>> aborted, because the simulated decider terminates.
>>>>>>>>>>
>>>>>>>>>
>>>>>>>>> typedef void (*ptr)();
>>>>>>>>> int HHH(ptr P);
>>>>>>>>>
>>>>>>>>> int DD()
>>>>>>>>> {
>>>>>>>>>   int Halt_Status = HHH(DD);
>>>>>>>>>   if (Halt_Status)
>>>>>>>>>     HERE: goto HERE;
>>>>>>>>>   return Halt_Status;
>>>>>>>>> }
>>>>>>>>>
>>>>>>>>> int main()
>>>>>>>>> {
>>>>>>>>>   HHH(DD);
>>>>>>>>> }
>>>>>>>>>
>>>>>>>>> Every simulated input that must be aborted to
>>>>>>>>> prevent the non-termination of HHH is stipulated
>>>>>>>>> to be correctly rejected by HHH as non-terminating.
>>>>>>>>>
>>>>>>>> A very strange and invalid stipulation.
>>>>>>>
>>>>>>> It merely means that the words do not have their ordinary meaning.
>>>
>>> Those two comments are not discussed below.
>>>
>>>>>> Unless HHH(DD) aborts its simulation of DD itself cannot possibly 
>>>>>> terminate normally.
>>>>>
>>>>> That cannot be determined without examination of HHH, which is not 
>>>>> in the
>>>>> scope of OP.
>>>>
>>>> I have given everyone here all of the complete source
>>>> code for a few years
>>>
>>> True but irrelevant. OP did not specify that HHH means that particular
>>> code.
>>>
>>
>> Every post that I have been talking about for two or
>> more years has referred to variations of that same code.
> 
> OP had a pointer of that code but didn's state that that code is a part
> of the problem. OP did not spacify any range for variation.
> 

I have only been talking about variations of the same code
as HHH(DD) for two years. Do you understand that one sentence?

-- 
Copyright 2025 Olcott "Talent hits a target no one else can hit; Genius
hits a target no one else can see." Arthur Schopenhauer