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From: dbush <dbush.mobile@gmail.com>
Newsgroups: comp.theory
Subject: Re: DD specifies non-terminating behavior to HHH ---USPTO
 Incorporation by reference --- despicable dishonesty
Date: Sat, 22 Feb 2025 21:41:07 -0500
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On 2/22/2025 7:45 PM, olcott wrote:
> On 2/22/2025 6:02 PM, Richard Damon wrote:
>> On 2/22/25 11:52 AM, olcott wrote:
>>> On 2/22/2025 5:05 AM, joes wrote:
>>>> Am Thu, 20 Feb 2025 18:25:27 -0600 schrieb olcott:
>>>>> On 2/20/2025 4:38 PM, Alan Mackenzie wrote:
>>>>>> olcott <polcott333@gmail.com> wrote:
>>>>>>> On 2/20/2025 2:38 AM, Mikko wrote:
>>>>>>>> On 2025-02-20 00:31:33 +0000, olcott said:
>>>>>>
>>>>>>>>> I have given everyone here all of the complete source code for 
>>>>>>>>> a few
>>>>>>>>> years
>>>>>>>> True but irrelevant. OP did not specify that HHH means that
>>>>>>>> particular code.
>>>>>>> Every post that I have been talking about for two or more years has
>>>>>>> referred to variations of that same code.
>>>>>> Yes.  It would be a relief if you could move on to posting something
>>>>>> new and fresh.
>>>>> As soon as people fully address rather than endlessly dodge my key
>>>>> points I will be done.
>>>> Honestly, you're gonna die first, one way or the other.
>>>>
>>>>> Let's start with a root point.
>>>>> All of the other points validate this root point.
>>>>> *Simulating termination analyzer HHH correctly determines*
>>>>> *the non-halt status of DD*
>>>> Since DD halts, that's dead in the water.
>>>>
>>>
>>> Despicably intentionally dishonest attempts at the straw-man
>>> deception aside:
>>>
>>> DD correctly simulated by HHH cannot possibly terminate
>>> normally by reaching its own "return" instruction.
>>>
>>
>> Only because that statement is based on a false premise.
>>
>> Since HHH doesn't correctly simulate its input, your statement is just 
>> a fabrication of your imagination.
> 
> *Correct simulation means emulates the machine code as specified*
> It cannot mean imagining a different sequence than the one that the 
> machine code specifies. That most people here are clueless about
> x86 machine code is far less than no rebuttal at all.
> 
> _DD()
> [00002133] 55         push ebp      ; housekeeping
> [00002134] 8bec       mov ebp,esp   ; housekeeping
> [00002136] 51         push ecx      ; make space for local
> [00002137] 6833210000 push 00002133 ; push DD
> [0000213c] e882f4ffff call 000015c3 ; call HHH(DD)
> [00002141] 83c404     add esp,+04
> [00002144] 8945fc     mov [ebp-04],eax
> [00002147] 837dfc00   cmp dword [ebp-04],+00
> [0000214b] 7402       jz 0000214f
> [0000214d] ebfe       jmp 0000214d
> [0000214f] 8b45fc     mov eax,[ebp-04]
> [00002152] 8be5       mov esp,ebp
> [00002154] 5d         pop ebp
> [00002155] c3         ret
> Size in bytes:(0035) [00002155]
> 
> When DD emulated by HHH calls HHH(DD) this call cannot
> possibly return to the emulator, conclusively proving
> that
> 
> DD correctly simulated by HHH cannot possibly terminate
> normally by reaching its own "return" instruction.
> 
> Assuming that it does return is simply stupid.
> 
> 

Similarly, when no_numbers_greater_than_10 emulated by F calls F(0) this 
call cannot possibly return to the emulator, conclusively proving that

no_numbers_greater_than_10 correctly emulated by F cannot possibly 
terminate normally by reaching its own "return" instruction

Therefore you believe that there is no natural number greater than 10.

Assuming that is does return is simply stupid.