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From: "Chris M. Thomasson" <chris.m.thomasson.1@gmail.com>
Newsgroups: sci.math
Subject: Re: New equation
Date: Sun, 2 Mar 2025 12:54:37 -0800
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On 3/2/2025 9:33 AM, efji wrote:
> Le 02/03/2025 à 18:10, Python a écrit :
>> Le 02/03/2025 à 17:32, Richard Hachel a écrit :
>>> Le 02/03/2025 à 06:06, Jim Burns a écrit :
>>>  ⎜
>>>> (a+b𝑖)+(c+d𝑖) = (a+c)+(b+d)𝑖
>>>
>>>  Yes.
>>>
>>>> (a+b𝑖)⋅(c+d𝑖) = (ac-bd)+(ad+bc)𝑖
>>>
>>>  No.
>>>
>>>  (a+b𝑖)⋅(c+d𝑖) = (ac+bd)+(ad+bc)𝑖
>>>
>>>
>>>  In all thing : (a+b𝑖)⋅(c+d𝑖) = (ac+bd)+(ad+bc)𝑖
>>>
>>
>> This is true in R(j) not in C.
>>
>> I posted about this yesterday. Did you even read my post?
>>
> 
> He probably read it and did not understand a single word :)
> 

Yikes!