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From: efji <efji@efi.efji>
Newsgroups: fr.sci.maths
Subject: =?UTF-8?Q?Re=3A_Nouvelle_=C3=A9quation_=C3=A0_racines_complexes?=
Date: Sun, 2 Mar 2025 22:07:14 +0100
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Le 02/03/2025 à 21:46, Richard Hachel a écrit :
> Le 02/03/2025 à 21:36, efji a écrit :
>> Le 02/03/2025 à 21:17, Richard Hachel a écrit :
> 
>> Typique...
>> (2i-4i)x = -2ix
> 
> Oui.
> 
>> = -2x

Quel tache...

(x-4i)*(x+2i) = x²-2x+8 pour tout x
=> x^2 - 2ix - 8i^2 = x²-2x+8 pour tout x
=> 1 = 1 (OK) ET -2i = -2 ET -8i^2 = 8
=> i=1 ET i^2=-1 => 1^2=-1

Niveau 2nd...

-- 
F.J.