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From: Mikko <mikko.levanto@iki.fi>
Newsgroups: comp.theory
Subject: Re: Failure to meet this challenge proves that all of my reviewers are wrong
Date: Mon, 3 Mar 2025 14:42:54 +0200
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On 2025-03-02 14:42:03 +0000, olcott said:

> HHH is an emulating termination analyzer that emulates
> the x86 machine code located at the address of a function
> using a fully functional x86 emulator.
> 
> When HHH recognizes a non-terminating pattern in the
> execution trace of its emulated input it aborts this
> emulation and returns 0.
> 
> typedef void (*ptr)();
> int HHH(ptr P);
> 
> int DD()
> {
>    int Halt_Status = HHH(DD);
>    if (Halt_Status)
>      HERE: goto HERE;
>    return Halt_Status;
> }
> 
> _DD()
> [00002133] 55         push ebp      ; housekeeping
> [00002134] 8bec       mov ebp,esp   ; housekeeping
> [00002136] 51         push ecx      ; make space for local
> [00002137] 6833210000 push 00002133 ; push DD
> [0000213c] e882f4ffff call 000015c3 ; call HHH(DD)
> [00002141] 83c404     add esp,+04
> [00002144] 8945fc     mov [ebp-04],eax
> [00002147] 837dfc00   cmp dword [ebp-04],+00
> [0000214b] 7402       jz 0000214f
> [0000214d] ebfe       jmp 0000214d
> [0000214f] 8b45fc     mov eax,[ebp-04]
> [00002152] 8be5       mov esp,ebp
> [00002154] 5d         pop ebp
> [00002155] c3         ret
> Size in bytes:(0035) [00002155]
> 
> I challenged everyone here to provide the machine address
> by machine address (AKA line by line) execution trace
> of DD correctly emulated by HHH that reaches its own
> "ret" instruction.
> 
> No one made any attempt to do this because they know that
> this would prove that they are stupidly wrong to say that
> my trace is incorrect.

Wrong conclusion. That sometthing is not proven only means it is unproeven.
It may be correct, it may be incorrect. Without a proof we can only say
that you claim more than you know.

-- 
Mikko