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From: olcott <polcott333@gmail.com>
Newsgroups: comp.theory
Subject: Re: DD correctly emulated by HHH --- Totally ignoring invalid
 rebuttals ---PSR---
Date: Sat, 8 Mar 2025 19:24:16 -0600
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On 3/8/2025 6:56 PM, dbush wrote:
> On 3/8/2025 7:29 PM, olcott wrote:
>> On 3/8/2025 5:31 PM, dbush wrote:
>>> On 3/8/2025 6:23 PM, olcott wrote:
>>>> On 3/8/2025 4:58 PM, dbush wrote:
>>>>> On 3/8/2025 5:42 PM, olcott wrote:
>>>>>> On 3/8/2025 9:00 AM, dbush wrote:
>>>>>>> On 3/8/2025 9:03 AM, olcott wrote:
>>>>>>>>
>>>>>>>> Apparently you don't understand that inputs to a
>>>>>>>> simulating termination analyzer specifying infinite
>>>>>>>> recursion or recursive emulation cannot possibly
>>>>>>>> reach their own final state and terminate normally.
>>>>>>>
>>>>>>> Apparently you don't understand that inputs to a termination 
>>>>>>> analyzer, simulating or otherwise, are specified by the 
>>>>>>> specification that is the halting function:
>>>>>>>
>>>>>>> (<X>,Y) maps to 1 if and only if X(Y) halts when executed directly
>>>>>>> (<X>,Y) maps to 0 if and only if X(Y) does not halt when executed
>>>>>>>
>>>>>>> And HHH(DD)==0 fails to meet the above specification
>>>>>>
>>>>>> *THIS IS A SEMANTIC TAUTOLOGY THUS IMPOSSIBLY FALSE*
>>>>>> Replacing the code of HHH with an unconditional simulator and 
>>>>>> subsequently running HHH(DD) cannot possibly reach
>>>>>> its own "ret" instruction and terminate normally
>>>>>> because DD calls HHH(DD) in recursive emulation.
>>>>>>
>>>>>> It is ridiculously stupid to believe that HHH must
>>>>>> report on behavior other than the above behavior.
>>>>>>
>>>>>
>>>>> It must if it is to be classified as a halt decider or termination 
>>>>> analyzer as per the definition.
>>>>
>>>> In other words you believe that HHH 
>>>
>>> Is required to map the halting function to meet the requirements to 
>>> be a halt decider / termination analyzer.
>>>
>>
>> HHH must map from the input finite string DD
>> to the behavior that this finite string specifies
> 
> And what it specifies, to be considered a solution to the halting 
> problem, is given by the specification:
> 
> Given any algorithm (i.e. a fixed immutable sequence of instructions) X 
> described as <X> with input Y:
> 
> A solution to the halting problem is an algorithm H that computes the 
> following mapping:
> 
> (<X>,Y) maps to 1 if and only if X(Y) halts when executed directly
> (<X>,Y) maps to 0 if and only if X(Y) does not halt when executed
> 

In the same way that Sum(5,3) == 9
That is misconception is very widely held
does not make it not a misconception.

It is your above crazy nonsense that I require complete
agreement with these exact words before moving on to
any other point:

DD correctly emulated by HHH cannot possibly reach
its own "ret" instruction and terminate normally
because DD calls HHH(DD) in recursive emulation.


-- 
Copyright 2025 Olcott "Talent hits a target no one else can hit; Genius
hits a target no one else can see." Arthur Schopenhauer