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From: olcott <polcott333@gmail.com>
Newsgroups: comp.theory
Subject: Re: Every sufficiently competent C programmer knows --- Semantic
 Property of Finite String
Date: Fri, 14 Mar 2025 11:39:11 -0500
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On 3/14/2025 9:10 AM, Richard Damon wrote:
> On 3/14/25 12:26 AM, olcott wrote:
>> On 3/13/2025 10:03 PM, Richard Damon wrote:
>>> On 3/13/25 10:05 PM, olcott wrote:
>>>> On 3/13/2025 6:09 PM, Richard Damon wrote:
>>>>> On 3/13/25 4:46 PM, olcott wrote:
>>>>>> On 3/13/2025 4:27 AM, joes wrote:
>>>>>>> Am Wed, 12 Mar 2025 21:41:34 -0500 schrieb olcott:
>>>>>>>> On 3/12/2025 7:56 PM, dbush wrote:
>>>>>>>>> On 3/12/2025 8:41 PM, olcott wrote:
>>>>>>>>>>
>>>>>>>>>> NOT WHEN IT IS STIPULATED THAT THE BEHAVIOR BEING MEASURED IS
>>>>>>>>>
>>>>>>>>> The direct execution of DDD
>>>>>>>>
>>>>>>>> is proven to be different than the behavior of DDD emulated by HHH
>>>>>>>> according to the semantics of the x86 language.
>>>>>>>
>>>>>>> Which is weird, considering that a simulator should produce the same
>>>>>>> behaviour.
>>>>>>>
>>>>>>>
>>>>>>>> DECIDERS ARE REQUIRED TO REPORT ON THE SEMANTIC OR SYNTACTIC 
>>>>>>>> PROPERTY OF
>>>>>>>> THEIR INPUT FINITE STRINGS.
>>>>>>> And not if the input called a different simulator that didn't abort.
>>>>>>>
>>>>>>
>>>>>> DDD correctly emulated by HHH cannot possibly
>>>>>> reach its own final state no matter what HHH
>>>>>> does.
>>>>>>
>>>>>> DDD correctly emulated by HHH1 does reach its
>>>>>> own final state.
>>>>>
>>>>> Which shows that HHH doesn't correctly emulate its input, unless 
>>>>> you just lied and gave the two programs different inputs.
>>>>>
>>>>
>>>> void DDD()
>>>> {
>>>>    HHH(DDD);
>>>>    return;
>>>> }
>>>>
>>>> Someone that is not a liar could explain exactly
>>>> how DDD emulated by HHH according to the semantics
>>>> of the C language must have the same behavior as
>>>> DDD emulated by HHH1 according to the semantics
>>>> of the C language.
>>>
>>> WHy? The above is NOT a program, as to be a program it needs the full 
>>> code of HHH included.
>>>
>>
>> That would be too confusing for this simple thought experiment.
>> The behavior of HHH is already fully specified.
>>
> 
> No, that is the method you use to hide your deception.
> 

HHH is specified to correctly simulate a finite number
of steps of DDD. THAT IS 100% OF EVERYTHING THAT HHH
DOES FOR THE PURPOSE OF THIS THOUGHT EXPERIMENT.

void DDD()
{
   HHH(DDD);
   return;
}

The semantics of the finite string input DDD to HHH specifies
that it will continue to call HHH(DDD) in recursive simulation.


-- 
Copyright 2025 Olcott "Talent hits a target no one else can hit; Genius
hits a target no one else can see." Arthur Schopenhauer