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From: olcott <polcott333@gmail.com>
Newsgroups: comp.theory
Subject: Re: Every sufficiently competent C programmer knows --- Paraphrase of
Sipser's agreement
Date: Sun, 16 Mar 2025 10:05:40 -0500
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On 3/16/2025 7:31 AM, joes wrote:
> Am Sat, 15 Mar 2025 16:27:00 -0500 schrieb olcott:
>> On 3/15/2025 5:12 AM, Mikko wrote:
>>> On 2025-03-14 14:39:30 +0000, olcott said:
>>>> On 3/14/2025 4:03 AM, Mikko wrote:
>>>>> On 2025-03-13 20:56:22 +0000, olcott said:
>>>>>> On 3/13/2025 4:22 AM, Mikko wrote:
>>>>>>> On 2025-03-13 00:36:04 +0000, olcott said:
>>>>>>>
>>>>>>>
>>>>>>>> void DDD()
>>>>>>>> {
>>>>>>>> HHH(DDD);
>>>>>>>> return;
>>>>>>>> }
>>>>>>>> int DD()
>>>>>>>> {
>>>>>>>> int Halt_Status = HHH(DD);
>>>>>>>> if (Halt_Status)
>>>>>>>> HERE: goto HERE;
>>>>>>>> return Halt_Status;
>>>>>>>> }
>>>>>>>>
>>>>>>>> When HHH correctly emulates N steps of the above functions none of
>>>>>>>> them can possibly reach their own "return" instruction and
>>>>>>>> terminate normally.
>>>>>>>
>>>>>>> Nevertheless, assuming HHH is a decider, Infinite_Loop and
>>>>>>> Infinite_Recursion specify a non-terminating behaviour, DDD
>>>>>>> specifies a terminating behaviour
>>>>>>
>>>>>> What is the sequence of machine language instructions of DDD
>>>>>> emulated by HHH such that DDD reaches its machine address 00002183?
>>>>>
>>>>> Irrelevant off-topic distraction.
>>>>
>>>> Proving that you don't have a clue that Rice's Theorem is anchored in
>>>> the behavior that its finite string input specifies.
>>>
>>> Another irrelevant off-topic distraction, this time involving a false
>>> claim.
>>> One can be a competent C programmer without knowing anyting about
>>> Rice's Theorem.
>> YES.
>>
>>> Rice's Theorem is about semantic properties in general, not just
>>> behaviours.
>>> The unsolvability of the halting problem is just a special case.
>>>
>> Does THE INPUT TO simulating termination analyzer HHH encode a C
>> function that reaches its "return"
>> instruction [WHEN SIMULATED BY HHH] (The definition of simulating
>> termination analyzer) ???
> That can't be right. Otherwise my simulator could just not simulate
> at all and say that no input halts.
>
Originally a "decider" was any TM that always stops
running for any reason.
In computability theory, a decider is a Turing
machine that halts for every input.[1]
https://en.wikipedia.org/wiki/Decider_(Turing_machine)
>> <MIT Professor Sipser agreed to ONLY these verbatim words 10/13/2022>
>> </MIT Professor Sipser agreed to ONLY these verbatim words 10/13/2022>
> key word "correctly"
>
*I anchored what correct emulation means now*
<Accurate Paraphrase>
If emulating termination analyzer H emulates its input
finite string D of x86 machine language instructions
according to the semantics of the x86 programming language
until H correctly determines that this emulated D cannot
possibly reach its own "ret" instruction in any finite
number of correctly emulated steps then
H can abort its emulation of input D and correctly report
that D specifies a non-halting sequence of configurations.
</Accurate Paraphrase>
--
Copyright 2025 Olcott "Talent hits a target no one else can hit; Genius
hits a target no one else can see." Arthur Schopenhauer