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From: FromTheRafters <FTR@nomail.afraid.org>
Newsgroups: sci.math
Subject: Re: The existence of dark numbers proved by the thinned out harmonic, series
Date: Tue, 18 Mar 2025 11:14:42 -0400
Organization: Peripheral Visions
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References: <vqrbtd$1chb7$2@solani.org> <vr3pvd$20r1$1@news.muc.de> <vr4cgl$3qbcs$3@dont-email.me> <vr6fgl$1uok$1@news.muc.de> <vr6tit$21dt9$1@dont-email.me> <vr71ea$qjf$1@news.muc.de> <vr774e$2a6rj$2@dont-email.me> <vr7ma8$2onbj$2@dont-email.me> <vr8arv$3dccd$1@dont-email.me> <vr9tha$pvuu$1@dont-email.me> <vr9url$q03i$2@dont-email.me> <vrbc8g$23ker$1@dont-email.me> <vrbek0$276rm$1@dont-email.me> <vrbfl1$27e67$1@dont-email.me> <vrbg13$28e26$1@dont-email.me> <vrbgkp$27e67$2@dont-email.me> <vrboaj$2d16$3@news.muc.de> <vrc25c$2ndfn$1@dont-email.me>
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After serious thinking WM wrote :
> On 18.03.2025 13:18, Alan Mackenzie wrote:
>> WM <wolfgang.mueckenheim@tha.de> wrote:
>
>>> All elements of ℕ are there. That is the assumption. If no greatest can
>>> be identified, then the reason are dark numbers.
>> 
>> No, the reason is that there is no greatest element.
>
> How can that be realizied? If all are there and all are smaller than omega, 
> tzen there is a greatest one

That is just your intuition making you think that. Try mathematical 
thought.