Path: news.eternal-september.org!eternal-september.org!.POSTED!not-for-mail
From: Codey Stamatelos Kang <oloc@cyod.gr>
Newsgroups: sci.physics.relativity
Subject: Re: Electron size, shape and spin.Confusion and conflicts with
 Einstein's 1905 SR.
Followup-To: sci.physics.relativity
Date: Mon, 24 Mar 2025 21:27:00 -0000 (UTC)
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rhertz wrote:

> On Mon, 24 Mar 2025 13:03:34 +0000, Paul.B.Andersen wrote:
>>> DEEPSEEK ANSWER:
>>> ----------------------------------------------------------
>>> 5. Conclusion The commenter is correct that directly measuring the L1
>>> frequency with a
>>> precision of ±0.025 Hz is unrealistic for a GPS receiver.
> 
> Imbecile, I was working with spread spectrum transmission when you were
>
> The next phase, involving RECURSIVE ALGORITHMS for refinement of FOUR
> DATA SETS start, which involves matrix operation and feedback. After
> three or four steps in the math of trilateration, the EXACT POSITION of
> the GPS receiver is obtained (within the error margins for such
> operation with only one carrier: L1).

completely nonsense, you contradict yourself. It's fourangulation, not 
triangulation. And you can detect four frequency signals out of a single 
signal, something called FFT etc. Here an example, 20 and 21 Hz signal 
from the received


%% frequency plot
%% Time specifications:
Fs = 10000;                      % samples per second
dt = 1/Fs;                     % seconds per sample
StartTime = 0;                  % seconds
StopTime = 2;                  % seconds
t = (StartTime : dt : StopTime-dt)';
N = size(t,1);

%% Sine wave:
FcA = 20;                       % hertz
sA = cos(2*pi*FcA*t);
FcB = 21;                       % hertz
sB = cos(2*pi*FcB*t);

fOut('sinus sumation, fft',1);
hSa = subplot(3,1,1);
plot(t,sA,'-b',"linewidth", 2);hold on;
plot(t,sB,'-g',"linewidth", 2),grid;
axis(hSa,[0, 2, -1.1, 1.1]);

sC = sA + sB;
hSb = subplot(3,1,2);
plot(t,sC,'-r',"linewidth", 3),grid;
axis(hSb,[0, 2, -2.2, 2.2]);

%% Fourier Transform:
X = fftshift(fft(sC));
%% Frequency specifications:
dF = Fs/N;                      		% hertz
f = -Fs/2 : dF : Fs/2-dF;           	% hertz

%% Plot the spectrum:
hS = subplot(3,1,3);
plot(f,abs(X)/N,'linewidth',3),grid;
axis(hS,[-1, 44, -.2, 1]);
xlabel('Frequency (in hertz)');
title('Magnitude Response');