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Path: ...!weretis.net!feeder9.news.weretis.net!news.quux.org!eternal-september.org!feeder3.eternal-september.org!news.eternal-september.org!eternal-september.org!.POSTED!not-for-mail From: FromTheRafters <FTR@nomail.afraid.org> Newsgroups: sci.math Subject: Re: The Reimann "Zeta" function: How can it ever converge? Date: Tue, 25 Mar 2025 16:58:28 -0400 Organization: Peripheral Visions Lines: 32 Message-ID: <vrv5dn$5b7d$1@dont-email.me> References: <vruvdb$mo0t$1@news.xmission.com> Reply-To: erratic.howard@gmail.com MIME-Version: 1.0 Content-Type: text/plain; charset="iso-8859-15"; format=flowed Content-Transfer-Encoding: 8bit Injection-Date: Tue, 25 Mar 2025 21:58:33 +0100 (CET) Injection-Info: dont-email.me; posting-host="cbf96b991a129ea8553ad2332a76c707"; logging-data="175341"; mail-complaints-to="abuse@eternal-september.org"; posting-account="U2FsdGVkX18gHbugQGDmOVXNsAKj6ogQDNObwZkvfjw=" Cancel-Lock: sha1:vgfPn3c+IHnXo+7pKXl7Jg7IbUI= X-Newsreader: MesNews/1.08.06.00-gb X-ICQ: 1701145376 Bytes: 1848 Kenny McCormack was thinking very hard : > So I was reading in Wikipedia about the Zeta function, which is defined as: > > Z(s) = 1/(1**s) + 1/(2**s) + 1/(3**s) + ... > > Both the domain and range are specified as the complex numbers. > > And it says that if s is a negative integers (-2, -4, -6, etc), then Z(s) > is zero. But that can't be right. But first, a little manipulation: > > Suppose s is -2: > > 1/(n**s), where s = -2 > > is: > > 1/(1/(n**2)) > > is: > > n**2 > > so, the sum is like: > > 1+4+9+16+25+... > > Which just grows without bounds. And is certainly never zero. > > So, is Wikipedia wrong? Or just a typo? It refers to the trivial zeroes of the function. I don't get the double asterisk's meaning.