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From: olcott <polcott333@gmail.com>
Newsgroups: comp.theory
Subject: Re: DDD specifies recursive emulation to HHH and halting to HHH1
Date: Fri, 28 Mar 2025 15:30:36 -0500
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On 3/28/2025 2:24 PM, dbush wrote:
> On 3/28/2025 3:21 PM, olcott wrote:
>> On 3/28/2025 4:43 AM, Fred. Zwarts wrote:
>>> Op 28.mrt.2025 om 03:13 schreef olcott:
>>>> On 3/27/2025 9:04 PM, Richard Damon wrote:
>>>>> On 3/27/25 9:07 PM, olcott wrote:
>>>>>> On 3/27/2025 7:38 PM, dbush wrote:
>>>>>>> On 3/27/2025 8:34 PM, olcott wrote:
>>>>>>>> On 3/27/2025 7:12 PM, dbush wrote:
>>>>>>>>> On 3/27/2025 8:11 PM, olcott wrote:
>>>>>>>>>> On 3/27/2025 7:02 PM, dbush wrote:
>>>>>>>>>>> On 3/27/2025 7:36 PM, olcott wrote:
>>>>>>>>>>>> On 3/27/2025 1:27 PM, dbush wrote:
>>>>>>>>>>>>> On 3/27/2025 1:50 PM, olcott wrote:
>>>>>>>>>>>>>> On 3/27/2025 2:18 AM, Fred. Zwarts wrote:
>>>>>>>>>>>>>>> Op 27.mrt.2025 om 04:09 schreef olcott:
>>>>>>>>>>>>>>>> On 3/26/2025 8:22 PM, Richard Damon wrote:
>>>>>>>>>>>>>>>>
>>>>>>>>>>>>>>>> _DDD()
>>>>>>>>>>>>>>>> [00002172] 55         push ebp      ; housekeeping
>>>>>>>>>>>>>>>> [00002173] 8bec       mov  ebp,esp  ; housekeeping
>>>>>>>>>>>>>>>> [00002175] 6872210000 push 00002172 ; push DDD
>>>>>>>>>>>>>>>> [0000217a] e853f4ffff call 000015d2 ; call HHH(DDD)
>>>>>>>>>>>>>>>> [0000217f] 83c404     add  esp,+04
>>>>>>>>>>>>>>>> [00002182] 5d         pop  ebp
>>>>>>>>>>>>>>>> [00002183] c3         ret
>>>>>>>>>>>>>>>> Size in bytes:(0018) [00002183]
>>>>>>>>>>>>>>>>
>>>>>>>>>>>>>>>>> Non-Halting is that the machine won't reach its final 
>>>>>>>>>>>>>>>>> staste even if an unbounded number of steps are 
>>>>>>>>>>>>>>>>> emulated. Since HHH doesn't do that, it isn't showing 
>>>>>>>>>>>>>>>>> non-halting.
>>>>>>>>>>>>>>>>>
>>>>>>>>>>>>>>>>
>>>>>>>>>>>>>>>> DDD emulated by any HHH will never reach its final state
>>>>>>>>>>>>>>>> in an unbounded number of steps.
>>>>>>>>>>>>>>>>
>>>>>>>>>>>>>>>> DDD emulated by HHH1 reaches its final state in a finite
>>>>>>>>>>>>>>>> number of steps.
>>>>>>>>>>>>>>>>
>>>>>>>>>>>>>>> It is not very interesting to know whether a simulator 
>>>>>>>>>>>>>>> reports that it is unable to reach the end of the 
>>>>>>>>>>>>>>> simulation of a program that halts in direct execution.
>>>>>>>>>>>>>>
>>>>>>>>>>>>>> That IS NOT what HHH is reporting.
>>>>>>>>>>>>>> HHH correctly rejects DDD because DDD correctly
>>>>>>>>>>>>>> emulated by HHH cannot possibly reach its own
>>>>>>>>>>>>>> final halt state.
>>>>>>>>>>>>>
>>>>>>>>>>>>> In other words, HHH is not a halt decider because it is not 
>>>>>>>>>>>>> computing the required mapping:
>>>>>>>>>>>>>
>>>>>>>>>>>>
>>>>>>>>>>>> Troll
>>>>>>>>>>>>
>>>>>>>>>>>
>>>>>>>>>>> On Monday, March 6, 2023 at 3:19:42 PM UTC-5, olcott wrote:
>>>>>>>>>>>  > In other words you could find any error in my post so you 
>>>>>>>>>>> resort to the
>>>>>>>>>>>  > lame tactic of ad hominem personal attack.
>>>>>>>>>>>
>>>>>>>>>>
>>>>>>>>>> Troll
>>>>>>>>>>
>>>>>>>>>
>>>>>>>>> On 7/22/2024 10:51 AM, olcott wrote:
>>>>>>>>>  > *Ad Hominem attacks are the first resort of clueless wonders*
>>>>>>>>>
>>>>>>>>
>>>>>>>> I corrected your error dozens of times and you
>>>>>>>> ignore these corrections and mindlessly repeat
>>>>>>>> your error like a bot 
>>>>>>>
>>>>>>> Which is what you've been doing for the last three years.
>>>>>>>
>>>>>>> Projection, as always.  I'll add the above to the list.
>>>>>>>
>>>>>>
>>>>>> TM's cannot possibly ever report on the behavior
>>>>>> of the direct execution of another TM. I proved
>>>>>> this many times in may ways. Ignoring these proofs
>>>>>> IT NOT ANY FORM OF REBUTTAL.
>>>>>>
>>>>>
>>>>> Sure they can.
>>>>>
>>>>> WHere is your proof? And what actual accepted principles is is 
>>>>> based on?
>>>>>
>>>>
>>>> No TM can take another directly executed TM as an input
>>>> and Turing computable functions only compute the mapping
>>>> from inputs to outputs.
>>>>
>>>
>>> If A TM can only compute the mapping from *its* input to *its* 
>>> output, it cannot be wrong.
>>
>> Taking a wild guess does not count as computing the mapping.
> 
> False.  The only requirement is to map a member of the input domain to a 
> member of the output domain as per the requirements.
> 
> If it does so in all cases, the mapping is computed.  It doesn't matter 
> how it's done.
> 

Unless an input is transformed into an output
on the basis of a syntactic or semantic property
of this input it is not a Turing computable function.

int StringLength(char *S)
{
   return 5;
}

Does not compute the string length of any string.

-- 
Copyright 2025 Olcott "Talent hits a target no one else can hit; Genius
hits a target no one else can see." Arthur Schopenhauer