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From: olcott <polcott333@gmail.com>
Newsgroups: comp.theory
Subject: Re: DDD specifies recursive emulation to HHH and halting to HHH1
Date: Sun, 30 Mar 2025 13:27:57 -0500
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On 3/30/2025 3:12 AM, joes wrote:
> Am Sat, 29 Mar 2025 16:46:26 -0500 schrieb olcott:
>> On 3/29/2025 3:14 PM, dbush wrote:
>>> On 3/29/2025 4:01 PM, olcott wrote:
> 
>>>> We can know that when this adapted UTM simulates a finite number of
>>>> steps of its input that this finite number of steps were simulated
>>>> correctly.
>>> And therefore does not do a correct UTM simulation that matches the
>>> behavior of the direct execution as it is incomplete.
>> It is dishonest to expect non-terminating inputs to complete.
> A complete simulation of a nonterminating input doesn't halt.
> 
>>>>> 2) changing the input is not allowed
>>>> The input is unchanged. There never was any indication that the input
>>>> was in any way changed.
>>> False, if the starting function calls UTM and UTM changes, you're
>>> changing the input.
>> When UTM1 is a UTM that has been adapted to only simulate a finite
>> number of steps
> So not an UTM.
> 
>> and input D calls UTM1 then the behavior of D simulated
>> by UTM1 never reaches its final halt state.
>> When D is simulated by ordinary UTM2 that D does not call Then D reaches
>> its final halt state.
> Doesn't matter if it calls it, but if the UTM halts.
> 
>>> Changing the input is not allowed.
>> I never changed the input. D always calls UTM1.
>> thus is the same input to UTM1 as it is to UTM2.
> You changed UTM1, which is part of the input D.
> 

UTM1 simulates D that calls UTM1
simulated D NEVER reaches final halt state

UTM2 simulates D that calls UTM1
simulated D ALWAYS reaches final halt state

-- 
Copyright 2025 Olcott "Talent hits a target no one else can hit; Genius
hits a target no one else can see." Arthur Schopenhauer