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From: olcott <polcott333@gmail.com>
Newsgroups: comp.theory
Subject: Re: DDD specifies recursive emulation to HHH and halting to HHH1
Date: Sun, 30 Mar 2025 22:16:28 -0500
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On 3/30/2025 9:40 PM, Richard Damon wrote:
> On 3/30/25 10:17 PM, olcott wrote:
>> On 3/30/2025 7:35 PM, Richard Damon wrote:
>>> On 3/30/25 5:56 PM, olcott wrote:
>>>> On 3/30/2025 4:05 PM, Richard Damon wrote:
>>>>> On 3/30/25 4:32 PM, olcott wrote:
>>>>>> On 3/30/2025 1:52 PM, Richard Damon wrote:
>>>>>>> On 3/30/25 2:27 PM, olcott wrote:
>>>>>>>> On 3/30/2025 3:12 AM, joes wrote:
>>>>>>>>> Am Sat, 29 Mar 2025 16:46:26 -0500 schrieb olcott:
>>>>>>>>>> On 3/29/2025 3:14 PM, dbush wrote:
>>>>>>>>>>> On 3/29/2025 4:01 PM, olcott wrote:
>>>>>>>>>
>>>>>>>>>>>> We can know that when this adapted UTM simulates a finite 
>>>>>>>>>>>> number of
>>>>>>>>>>>> steps of its input that this finite number of steps were 
>>>>>>>>>>>> simulated
>>>>>>>>>>>> correctly.
>>>>>>>>>>> And therefore does not do a correct UTM simulation that 
>>>>>>>>>>> matches the
>>>>>>>>>>> behavior of the direct execution as it is incomplete.
>>>>>>>>>> It is dishonest to expect non-terminating inputs to complete.
>>>>>>>>> A complete simulation of a nonterminating input doesn't halt.
>>>>>>>>>
>>>>>>>>>>>>> 2) changing the input is not allowed
>>>>>>>>>>>> The input is unchanged. There never was any indication that 
>>>>>>>>>>>> the input
>>>>>>>>>>>> was in any way changed.
>>>>>>>>>>> False, if the starting function calls UTM and UTM changes, 
>>>>>>>>>>> you're
>>>>>>>>>>> changing the input.
>>>>>>>>>> When UTM1 is a UTM that has been adapted to only simulate a 
>>>>>>>>>> finite
>>>>>>>>>> number of steps
>>>>>>>>> So not an UTM.
>>>>>>>>>
>>>>>>>>>> and input D calls UTM1 then the behavior of D simulated
>>>>>>>>>> by UTM1 never reaches its final halt state.
>>>>>>>>>> When D is simulated by ordinary UTM2 that D does not call Then 
>>>>>>>>>> D reaches
>>>>>>>>>> its final halt state.
>>>>>>>>> Doesn't matter if it calls it, but if the UTM halts.
>>>>>>>>>
>>>>>>>>>>> Changing the input is not allowed.
>>>>>>>>>> I never changed the input. D always calls UTM1.
>>>>>>>>>> thus is the same input to UTM1 as it is to UTM2.
>>>>>>>>> You changed UTM1, which is part of the input D.
>>>>>>>>>
>>>>>>>>
>>>>>>>> UTM1 simulates D that calls UTM1
>>>>>>>> simulated D NEVER reaches final halt state
>>>>>>>>
>>>>>>>> UTM2 simulates D that calls UTM1
>>>>>>>> simulated D ALWAYS reaches final halt state
>>>>>>>>
>>>>>>>
>>>>>>> Only because UTM1 isn't actually a UTM, but a LIE since it only 
>>>>>>> does a partial simulation, not a complete as REQURIED by the 
>>>>>>> definition of a UTM.
>>>>>>>
>>>>>>
>>>>>> _DDD()
>>>>>> [00002172] 55         push ebp      ; housekeeping
>>>>>> [00002173] 8bec       mov  ebp,esp  ; housekeeping
>>>>>> [00002175] 6872210000 push 00002172 ; push DDD
>>>>>> [0000217a] e853f4ffff call 000015d2 ; call HHH(DDD)
>>>>>> [0000217f] 83c404     add  esp,+04
>>>>>> [00002182] 5d         pop  ebp
>>>>>> [00002183] c3         ret
>>>>>> Size in bytes:(0018) [00002183]
>>>>>>
>>>>>> DDD EMULATED BY HHH DOES SPECIFY THAT IT
>>>>>> CANNOT POSSIBLY REACH ITS OWN FINAL HALT STATE.
>>>>>>
>>>>>> THAT IS WHAT IT SAYS AND ANYONE THAT DISAGREES
>>>>>> IS A DAMNED LIAR OR STUPID.
>>>>>>
>>>>>
>>>>> How is that DDD correctly emulated beyond the call HHH instruction 
>>>>> by a program that is a pure function, and thus only looks at its 
>>>>> input?
>>>>>
>>>>
>>>> *THE ENTIRE SCOPE IS*
>>>> DDD EMULATED BY HHH DOES SPECIFY THAT IT
>>>> CANNOT POSSIBLY REACH ITS OWN FINAL HALT STATE.
>>>
>>>  From where? Remember, the Halting problem is SPECIFICALLY 
>>
>> OFF F-CKING TOPIC. WE ABOUT ONE F-CKING STEP OF MY PROOF.
>> WE HAVE BEEN TALKING ABOUT ONE F-CKING STEP OF MY PROOF
>> FOR THREE F-CKING YEARS.
>>
>> DDD correctly emulated by HHH DOES NOT F-CKING HALT !!!
>>
>>
> 
> Your proof is just off topic ranting.
> 
> The problem is that DDD is NOT correctly emulated by HHH, 

You are a damned liar when you try to get away
with implying that HHH does not emulate itself
emulating DDD in recursive emulation according
to the semantics of the x86 language.


-- 
Copyright 2025 Olcott "Talent hits a target no one else can hit; Genius
hits a target no one else can see." Arthur Schopenhauer