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From: "Fred. Zwarts" <F.Zwarts@HetNet.nl>
Newsgroups: comp.theory
Subject: Re: DDD specifies recursive emulation to HHH and halting to HHH1 ---
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Date: Thu, 3 Apr 2025 11:02:56 +0200
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Op 03.apr.2025 om 04:37 schreef olcott:
> On 4/2/2025 6:16 AM, Richard Damon wrote:
>> On 4/1/25 10:37 PM, olcott wrote:
>>> On 4/1/2025 8:13 PM, Richard Damon wrote:
>>>> On 4/1/25 7:35 PM, olcott wrote:
>>>>> On 4/1/2025 5:36 AM, Richard Damon wrote:
>>>>>> On 3/31/25 10:19 PM, olcott wrote:
>>>>>>>
>>>>>>> *Simulating termination analyzer Principle*
>>>>>>> It is always correct for any simulating termination
>>>>>>> analyzer to stop simulating and reject any input
>>>>>>> that would otherwise prevent its own termination.
>>>>>>>
>>>>>>
>>>>>> But DDD doesn't prevent its own terminatation, as it calls an HHH 
>>>>>> that WILL abort its emulation and return and answer.
>>>>>>
>>>>>
>>>>> You know that DDD stopping running and DDD reaching its
>>>>> final halt state are not the same thing you damned liar.
>>>>>
>>>>
>>>> Right, the DDD who's simulation is stopped hasn't shown non-halting 
>>>> behavior, just not-yet-halted.
>>>>
>>>
>>> You already admitted that you are lying about this.
>>> DDD emulated by HHH for an infinite number of steps
>>> never reaches its final halt state.
>>
>> But that isn't something that happens with THIS HHH, since it doesn't 
>> do that.
>>
> 
> 
> When DDD emulated by HHH for an infinite number of steps
> never halts then as soon as HHH correctly infers this it
> has its basis to reject DDD.
> 
Dreaming again of an infinite recursion? Dreams are no substitute for 
logic. HHH emulates only a finite number of steps. That is exactly what 
makes it halting and what makes DDD halting.