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From: dbush <dbush.mobile@gmail.com>
Newsgroups: comp.lang.c
Subject: Re: DD simulated by HHH cannot possibly halt (Halting Problem)
Date: Sat, 5 Apr 2025 17:59:23 -0400
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On 4/5/2025 5:56 PM, olcott wrote:
> On 4/5/2025 4:48 PM, dbush wrote:
>> On 4/5/2025 5:40 PM, olcott wrote:
>>> On 4/5/2025 4:14 PM, dbush wrote:
>>>> On 4/5/2025 3:01 PM, olcott wrote:
>>>>> On 4/5/2025 1:45 PM, Richard Heathfield wrote:
>>>>>> On 05/04/2025 19:11, olcott wrote:
>>>>>>> On 4/5/2025 11:25 AM, dbush wrote:
>>>>>
>>>>>>>> On 4/5/2025 11:59 AM, olcott wrote:>>>>
>>>>>>>>> Introduction to the Theory of Computation 3rd Edition
>>>>>>>>> by Michael Sipser (Author) (best selling textbook)
>>>>>>>>>
>>>>>>>>> <MIT Professor Sipser agreed to ONLY these verbatim words
>>>>>>>>> 10/13/2022>
>>>>>>>>> If simulating halt decider H correctly simulates its input D
>>>>>>>>> until H correctly determines that its simulated D would never
>>>>>>>>> stop running unless aborted then
>>>>>>>>>
>>>>>>>>> H can abort its simulation of D and correctly report that D
>>>>>>>>> specifies a non-halting sequence of configurations.
>>>>>>>>> </MIT Professor Sipser agreed to ONLY these verbatim words
>>>>>>>>> 10/13/2022>
>>>>>>>>
>>>>>>>> But not what you think he agreed to:
>>>>>>>>
>>>>>>>>
>>>>>
>>>>> void DDD()
>>>>> {
>>>>> HHH(DDD);
>>>>> return;
>>>>> }
>>>>>
>>>>>>>
>>>>>>> You have to show that by showing the details of how
>>>>>>> what he agreed to is not accurately paraphrased by
>>>>>>> *Simulating termination analyzer Principle*
>>>>>>
>>>>>> No, you have to show firstly that your H determines anything at
>>>>>> all about D's behaviour.
>>>>>
>>>>> First of all it is the concrete DDD and the hypothetical HHH.
>>>>
>>>> Category error. The algorithm DDD is not fully specified if the
>>>> code of the function HHH and everything it calls explicitly spelled
>>>> out, as all of that is the code under test.
>>>
>>> DDD meets the spec of the
>>> *Simulating termination analyzer Principle*
>>> as long as HHH emulates enough steps of DDD
>>> to see that it must stop simulating DDD.
>>>
>>
>> And as such is unrelated to the halting problem, as the halting
>> problem is about algorithms, and DDD as you've defined it is not an
>> algorithm:
>>
>
> OK great we are making progress.
> You agree that the specified DDD and a
> hypothetical HHH could meet the
> *Simulating termination analyzer Principle*
>
Which you will be unable to link back to the halting problem:
Given any algorithm (i.e. a fixed immutable sequence of instructions) X
described as <X> with input Y:
A solution to the halting problem is an algorithm H that computes the
following mapping:
(<X>,Y) maps to 1 if and only if X(Y) halts when executed directly
(<X>,Y) maps to 0 if and only if X(Y) does not halt when executed directly